Answer:
The beryllium atom; 1.99 times larger.
Step-by-step explanation:
The beryllium atom is 0.000000000112 meters, while the nitrogen atom is 0.000000000056 meters. So, the beryllium atom is larger than the other.
(1.12 * 10^-10) / (5.6 * 10^-11)
= (1.112 / 5.6) * (10^-10 + 11)
= 0.1985714286 * 10
= 1.985714286 * 10^0
So, the beryllium atom is about 1.99 times larger than the other.
Hope this helps!
Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
Answer:
The probability that a worker was taught by method A given that he learned the skill successfully is 0.72.
Step-by-step explanation:
(1)
The information provided is:
<em>A</em> = if method A is used
<em>B</em> = if method B is used
<em>S</em> = successfully learning the skill
P (A) = 0.75
P (B) = 0.25
P (S|A) = 0.80
P (S|B) = 0.95
Compute the probability that a worker was taught by method A given that he learned the skill successfully as follows:
Thus, the probability that a worker was taught by method A given that he learned the skill successfully is 0.72.
(2)
The probability is attached below.
14 i’m guessing because if you add the 2 years it’s 9 + 5 is 14
