Question

Ionic Equations.

Answer 1

Answer :

When we are writing the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : It is defined as the ions present on reactant and product side which do not participate in a chemical reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$Na_2CO_3(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2CO_3(s)$

The ionic equation in separated aqueous solution will be,

$2Na^+(aq)+CO_3^{2-}(aq)+2Ag^+(aq)+2NO_3^-(aq)\rightarrow 2Na^++2NO_3^-(aq)+Ag_2CO_3(s)$

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2Ag^+(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)$

Answer 2

B.) 2na+(aq)+co3(aq)+ ag+(aq) + no3-(aq) ---> na+(aq) + no3-(aq) + ag2co3(s)

So to get the net ionic equation cancel the ions that paper on both side like cancel the na+ and the no3-