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solong [7]
3 years ago
11

Examination reveals that 180.2 g/mol of glucose contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen.

How many g of hydrogen are there in 55.5 g of glucose?
Chemistry
1 answer:
jeka57 [31]3 years ago
3 0

Mass of Hydrogen = 3.7 g

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

180.2 g/mol of glucose-C₆H₁₂O₆ contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen

Remainder Hydrogen :

\tt 180-(72.1+96)=11.9~g/mol

% mass of Hidrogen in Gllucose :

\tt \dfrac{11.9}{180}\times 100\%=6.61\%

So mass of Hydrogen in 55.5 g Glucose :

\tt 6.61\%\times 55.5~g=3.7~g

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Explanation:

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Select the correct electron configuration for Boron. (Atomic Number 5) 1s 22s 12p 2 1s 22s 3 1s 32s 12p 1 1s 22s 22p 1
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ans is: 1s2, 2s2 ,2p1,...

7 0
3 years ago
Now select a longer period, say the fourth period, starting with the element in the 1A group. Again, go from left to right. What
Inessa [10]

Answer:

The pattern of change in the electron configuration increases from left to right across the period.

Explanation:

In the periodic table, elements having the same number of electrons in the outermost shell of their atoms are placed over one another in vertical columns. Each of the vertical columns is known as a group or family. while each of the resulting horizontal rows is known as a period or row.

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The electron distribution into the energy levels of sublevels of atoms  can be shown in any of the tree important electronic configuration.

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In the Periodic table ,The sublevels with lower energies are filled  up before those with higher energies. One important thing about this principle is that the sublevels do not fill up in numerical order. The pattern of filling is as follows:

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5 0
3 years ago
A 25.0 g bold made of an alloy absorbed 250 J of heat as its temperature changed from 25.0 °C to 78.0 °C. What is the specific h
nata0808 [166]

Answer:

Specific heat of alloy = 0.2 j/ g.°C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of bold = 25 g

Heat absorbed = 250 J

Initial Temperature = 25°C

Final temperature = 78°C

Specific heat of alloy = ?

Solution:

Change in temperature:

ΔT = 78°C - 25°C

ΔT = 53°C

Now we will put the values in formula.

Q = m.c. ΔT

250 j = 25 g × c ×53°C

250 j = 1325 g.°C × c

250 j / 1325 g.°C = c

c = 0.2 j/ g.°C

8 0
3 years ago
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