1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solong [7]
3 years ago
11

Examination reveals that 180.2 g/mol of glucose contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen.

How many g of hydrogen are there in 55.5 g of glucose?
Chemistry
1 answer:
jeka57 [31]3 years ago
3 0

Mass of Hydrogen = 3.7 g

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

180.2 g/mol of glucose-C₆H₁₂O₆ contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen

Remainder Hydrogen :

\tt 180-(72.1+96)=11.9~g/mol

% mass of Hidrogen in Gllucose :

\tt \dfrac{11.9}{180}\times 100\%=6.61\%

So mass of Hydrogen in 55.5 g Glucose :

\tt 6.61\%\times 55.5~g=3.7~g

You might be interested in
When 2.00 g of methane are burned in a bomb calorimeter, the change in temperature is 3.08°C. The heat capacity of the calorimet
melisa1 [442]

Answer:

The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

q=c\times \Delta T

where,

q = Heat gained = ?

c = Specific heat = 2.68 kJ/^oC

ΔT =  The change in temperature = 3.08°C

Now put all the given values in the above formula, we get:

q=2.68 kJ/^oC\times 3.08^oC

q=8.2544 kJ

Now we have to calculate molar enthalpy of combustion of this substance :

\Delta H_{comb}=-\frac{q}{n}

where,

\Delta H_{comb} = enthalpy change = ?

q = heat gained = 8.2544kJ

n = number of moles methane = \frac{\text{Mass of methane}}{\text{Molar mass of methane }}=\frac{2.00 g}{16.042 g/mol}=0.1247 mole

\Delta H_{comb}=-\frac{8.2544 kJ}{0.1247 mole}=-66.21 kJ/mole\approx -66 kJ/mole

Therefore,  the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

6 0
3 years ago
_KOH + _H₂PO4 → _K₂PO4 + _H₂O​
Hunter-Best [27]

Answer:

2KOH+H2PO4--K2PO4+4H2O

3 0
3 years ago
I’ll give brainliest!! I am a flat surface with one higher than the other. I make moving loads
Anit [1.1K]

Answer:a inclined plane

Explanation:    like a ramp

6 0
2 years ago
Read 2 more answers
Raising or lowering temperature. What happens to the pressure? Is this a direct or indirect relationship?
Dahasolnce [82]

Answer:

sorry I didn't understand this question

4 0
3 years ago
What kind of reaction is the equation?<br> Zn(s) + 2HCl(aq) → ZnCl2 (aq) + H2(g) + heat
QveST [7]
Given the balanced equation representing a reaction: Zn(s) + 2HCl(aq) + H2(g) + ZnCl2(aq) Which statement is true about energy in this reaction? A. The reaction is exothermic because it releases heat.
3 0
2 years ago
Other questions:
  • What happens to chemical bonds between atoms or ions during a chemical reaction?
    14·1 answer
  • An unknown liquid has a mass of 4.25 × 108 mg and a volume of 0.250 m3. what is the density of the liquid in units of g/ml?
    11·2 answers
  • An organism that is able to form nutritional organic substances from simple inorganic
    13·1 answer
  • How many atoms are in 131.97 liters of water vapor at STP?
    11·1 answer
  • Which question is most important to developmental psychology?
    9·1 answer
  • Which of the following materials is most effective for stopping gamma radiation?
    13·1 answer
  • What part of the stem transports water and nutrients to the rest of the plant?
    7·1 answer
  • A) what is hydrogen's carrying capacity? <br> b) what is lithium’s carrying capacity?
    6·1 answer
  • Help me please do this Question :)
    6·1 answer
  • Calcium + sulfuric acid =
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!