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solong [7]
3 years ago
11

Examination reveals that 180.2 g/mol of glucose contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen.

How many g of hydrogen are there in 55.5 g of glucose?
Chemistry
1 answer:
jeka57 [31]3 years ago
3 0

Mass of Hydrogen = 3.7 g

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

180.2 g/mol of glucose-C₆H₁₂O₆ contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen

Remainder Hydrogen :

\tt 180-(72.1+96)=11.9~g/mol

% mass of Hidrogen in Gllucose :

\tt \dfrac{11.9}{180}\times 100\%=6.61\%

So mass of Hydrogen in 55.5 g Glucose :

\tt 6.61\%\times 55.5~g=3.7~g

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Size and Temperature or E & B

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Carboxylic acid

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7 0
3 years ago
(PLZ ANSWER SOON)
almond37 [142]

Answer:

10.5 k.J.

Explanation:

7 0
3 years ago
Use standard enthalpies of formation to calculate Δ H ∘ rxn for each reaction. MISSED THIS? Read Section 7.9; Watch KCV 7.9, IWE
Eva8 [605]

Answer:

Standard Heat of Reaction 1 = -136.2 kJ/mol

Standard Heat of Reaction 2 = -41.166 kJ/mol

Standard Heat of Reaction 3 = -136.07 kJ/mol

Standard Heat of Reaction 4 = 279.448kJ/mol

Explanation:

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

The required standard heat of formation for each of the reactants and product above, as obtained from literature is listed below.

C₂H₄ (g), 52.5 kJ/mol

H₂ (g), 0 kJ/mol

C₂H₆ (g), -83.7 kJ/mol

CO (g), -110.525 kJ/mol

H₂O (g), -241.818 kJ/mol

H₂ (g), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

NO₂ (g), 33.2 kJ/mol

H₂O (l), -285.8 kJ/mol

HNO₃ (aq), -206.28 kJ/mol

NO (g), 90.29 kJ/mol

Cr₂O₃ (s), -1128.4 kJ/mol

CO (g), -110.525 kJ/mol

Cr (s), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

Note that

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (1×-83.7) = -83.7 kJ/mol

ΔH∘(reactants) = (1×52.5) + (1×0) = 52.5 kJ/mol

ΔH∘(rxn) = -83.7 - 52.5 = -136.2 kJ/mol

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (1×0) + (1×-393.509) = -393.509 kJ/mol

ΔH∘(reactants) = (1×-110.525) + (1×-241.818) = -352.343 kJ/mol

ΔH∘(rxn) = -393.509 - (-352.343) = -41.166 kJ/mol

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (2×-206.28) + (1×90.29) = -322.27 kJ/mol

ΔH∘(reactants) = (3×33.2) + (1×-285.8) = -186.2 kJ/mol

ΔH∘(rxn) = -322.27 - (-186.2) = -136.07 kJ/mol

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (2×0) + (3×-393.509) = -1,180.527 kJ/mol

ΔH∘(reactants) = (1×-1128.4) + (3×-110.525) = -1,459.975 kJ/mol

ΔH∘(rxn) = -1,180.527 - (-1,459.975) = 279.448 kJ/mol

Hope this Helps!!!

4 0
3 years ago
100 points
nordsb [41]

Hello!

My argument: Which is better a Ps4 or an Xbox 1


The Ps4 is a better all-round console. The PS4 costs $100 less but has less games than the Xbox 1. The Xbox 1 now came up with dual compatible games. This means that certain games can now run on the Xbox 1 and the Xbox 360. The overall winner is really undetermined. The controller for Xbox has more quicker response time and is specifically built to be an extremely comfortable in your hands. Unlike the PS4 which their controller is built for nothing they really didn't do anything to theirs. Although the console comparisons are the same. The hard drive for the Xbox is non- removable meaning that if you want the hard drive. you would have to break the Xbox to get it . Unlike the Ps4 when you can take it out easily and switch it with any console and still have your data. I am an Xbox fan since for ever but I think that the two consoles are built the same.


Hope it helps!



7 0
3 years ago
Read 2 more answers
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