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Elena L [17]
3 years ago
12

What is the range of the data vaules 777521001346

Mathematics
1 answer:
Darya [45]3 years ago
4 0

Answer:

7

Step-by-step explanation:

range=largest number-smallest number

=7-0

=0

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Enter the appropriate value to answer the question or solve the problem.
Licemer1 [7]

Answer:

slope 2.500

x intercept 1.80000

m intercept 4.50000

Step-by-step explanation:

<u>step 1:</u>

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     5*(x+4)-(-2*(-4-m)+3)=0 

<u>step</u><u> </u><u>2</u><u>:</u>

   -4 - m  =   -1 • (m + 4) 

(5•(x+4))-((0--2•(m+4))+3) = 0

<em>step</em><em> </em><em>3</em><em>:</em>

5 • (x + 4) - (2m + 11) = 0

<u>step</u><u> </u><u>4</u><u>:</u>

5x - 2m + 9 = 0

<u>step</u><u> </u><u>5</u><u>:</u>

 Solve   5x-2m+9  = 0

3 0
2 years ago
How do i do this ???
Westkost [7]

a peculiar thing about the centroid of a triangle, is that it cuts all the medians in a 2:1 ratio, so JP : PM are on a 2:1 ratio, thus

\bf JP:PM\qquad 2:1\qquad \cfrac{JP}{PM}=\cfrac{2}{1}\implies \cfrac{27}{PM}=\cfrac{2}{1}\implies \cfrac{27}{2}=PM\\\\-------------------------------\\\\JM=JP+PM\implies JM=27+\cfrac{27}{2}\implies JM=\cfrac{54+27}{2}\\\\\\JM=\cfrac{81}{2}\implies JM=40\frac{1}{2}

4 0
3 years ago
Find the solution 4x&lt;8
Nataliya [291]

x=1

...................

7 0
2 years ago
A. 0.1925<br> B.0.1575<br> C.0.2925<br> D.0.3575<br><br> HELP PLEASE!!!
Elena-2011 [213]
A, because:

Hardcover: 0.35
Buys hard cover and non-fiction: 0.35 x 0.55 = 0.1925
3 0
3 years ago
A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

                                                                                                            = $10,000

If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

                                                         = (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0
2 years ago
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