Question

The equation shows a --the breaking and forming of chemical bonds that leads to a change in the composition of matter. 2. In the equation, CO2 is a . 3. In the equation, C6H12O6 is a . 4. In O2, the type of bond that holds the two oxygen atoms together is a . 5. In H2O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a . 6. The number of oxygen atoms on the left side of the equation is the number of oxygen atoms on the right side.

Answer 1

Explanation:

when electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.8 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.8 or greater than the bond formed is ionic in nature.

According to the given fill ups, the reaction equation is as follows.

   $C_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O$

This means the new products are formed due to the change in chemical composition of the reactants.

• Hence, the equation shows a chemical reaction - the breaking and forming of chemical bonds that leads to a change in the composition of matter.

• And, in the given equation $CO_{2}$ is a product.

• In the equation, $C_{6}H_{12}O_{6}$ is reactant.

• In $O_{2}$, the type of bond that holds the two oxygen atoms together is a non-polar covalent bond.

• In $H_{2}O$, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a polar covalent bond.

• The number of oxygen atoms on the left side of the equation is equal to the number of oxygen atoms on the right side.