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OlgaM077 [116]
3 years ago
7

Pls fast pls due today pls pls I don’t wanna fail

Chemistry
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

2:true

3: true

4:false

5: true

Explanation:

You might be interested in
Protists are prokaryotes. t or f
fredd [130]
Protists are NOT prokaryotes so the answer would be B) False.
7 0
3 years ago
What is the rate of the reaction when the initial concentration of no is 0.400 m and that of br2 is 0.245 m ?
Hoochie [10]
If the final concentration of NOBr = 0.250M
Change in concentration of NOBr = +0.250 M
Change in concentration of NO = -0.250 M
Change is concentration of Br2 = -0.125 M ( since number of moles of Br2 is 0.5 times the number of mole of NOBr)
Final concentration of NO = 0.400-0.250 = 0.150 M
Final concentration of Br2 = 0.245 - 0.125 M = 0.0120 M
Therefore;
Kc = conc (NOBr)^2/ ((conc NO)^2 ×(conc (Br2)
     = (0.250²)/(0.150²×0.120)
      = 23.148
      = 23.1 mol/dm³
8 0
3 years ago
Calcium and bromine have formed a bond. Leading up to this, calcium gave up electrons. It was a(n) ____.
Ugo [173]

<u><em>Answer:</em></u>

It was a positive ion.

<u><em>Explanation</em></u>

In CaBr, ionic bond is present. When one of the atom loses electrons and gets positive charges and other atom gains electrons and become negative. As a result of positive and nagative charges , a ionic bond formed.

As in this case, Ca loses electrons and become positive ion while on the other hand bromide gets the electrons and become negative ion.

<em>Note:</em>

Electropositive atoms always loose electrons Like Ca while electronegative atoms always gain elelctrons like Br.

5 0
4 years ago
Read 2 more answers
The equation to calculate density is D = m/v. For a liquid substance, which item increases as heatis applied?
Aleksandr [31]

Answer:

Both Density and Volume increase

Explanation:

5 0
4 years ago
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mo
aleksandrvk [35]

Explanation:

Relation between temperature and activation energy according to Arrhenius equation is as follows.

            k = A exp^{\frac{-E_{a}}{RT}}

where,   k = rate constant

              A = pre-exponential factor

           E_{a} = activation energy

             R = gas constant

              T = temperature in kelvin

Also,  

         ln (\frac{k_{2}}{k_{1}}) = (\frac{-E_{a}}{R}) \times (\frac{1}{T_{2}} - \frac{1}{T_{2}})

      T_{1} = 244^{o}C = (244 + 273) K = 517.15 K

      T_{2} = 324^{o}C = (597.15 + 273) K = 597.15 K

     k_{1} = 6.7 M^{-1} s^{-1},     k_{2} = ?

         R = 8.314 J/mol K

      E_{a} = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows.

   ln (\frac{k_{2}}{6.7}) = (\frac{-71000}{8.314} \times (\frac{1}{597.15} - \frac{1}{517.15})

                   = 2.2123

        \frac{k_{2}}{6.7} = exp(2.2123)

                    = 9.1364

                k_{2} = 61 M^{-1}s^{-1}

Thus, we can conclude that rate constant of this reaction is 61 M^{-1}s^{-1}.

3 0
3 years ago
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