Both compounds A and B have molecular formula C6H14. Monochlorination of compound A results in the formation of two constitution
al isomers. Monochlorination of compound B results in the formation of four constitutional isomers. Identify compounds A and B, and show the products of each monochlorination.
1) Draw compound A and the products of its monochlorination.
2)Draw compound B and the products of its monochlorination.
1) Draw compound A and the products of its monochlorination.
2)Draw compound B and the products of its monochlorination.
1 answer:
Answer:
The name of the two compounds will be:
A :2,2-dimethylbutane
B: 3-methylpentane
Explanation:
The compounds are the isomers of hexane as per the given molecular formula.
There is no unsaturation or no ring is present in the compound.
Constitutional isomers are the one which have different arrangement of chain.
The possible compounds are shown in the figure with the products of monochlorination of the two isomers.
Thus there are five possible isomers of hexane.
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Answer : The final temperature of the copper is,
Solution :
Formula used :
where,
Q = heat gained = 299 cal
m = mass of copper = 52 g
c = specific heat of copper =
= final temperature = ?
= initial temperature =
Now put all the given values in the above formula, we get the final temperature of copper.
Therefore, the final temperature of the copper is,