Both compounds A and B have molecular formula C6H14. Monochlorination of compound A results in the formation of two constitution
al isomers. Monochlorination of compound B results in the formation of four constitutional isomers. Identify compounds A and B, and show the products of each monochlorination.
1) Draw compound A and the products of its monochlorination.
2)Draw compound B and the products of its monochlorination.
1) Draw compound A and the products of its monochlorination.
2)Draw compound B and the products of its monochlorination.
1 answer:
Answer:
The name of the two compounds will be:
A :2,2-dimethylbutane
B: 3-methylpentane
Explanation:
The compounds are the isomers of hexane as per the given molecular formula.
There is no unsaturation or no ring is present in the compound.
Constitutional isomers are the one which have different arrangement of chain.
The possible compounds are shown in the figure with the products of monochlorination of the two isomers.
Thus there are five possible isomers of hexane.
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Answer:
The weight of ammonium phosphate is 10 gm
Explanation:
The chemical reaction of ammonium phosphate formation is as follows.
From the reaction one mole of phosphoric acid is equivalent to the one mole of ammonium phosphate.
So, "n" mole of phosphoric acid is equivalent to the "n" mole of ammonium phosphate.
Number of moles in 7.1 grams of phosphoric acid =
<u>Formation weight of ammonium phosphate :</u>
Weight of ammonium phosphate =
Round the answer to 2 significant digits
Weight of ammonium phosphate = 10 gm