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ikadub [295]
2 years ago
13

Two compounds might have spots with the same rf value in a chromatography experiment and not be identical compounds. Which propo

sed chromatography experiment could best help determine whether the compounds are identical?.
Chemistry
1 answer:
lys-0071 [83]2 years ago
5 0

The repeat of the original chromatography experiment with a different solvent might could best help determine whether the compounds are identical.

<h3>What is chromatography?</h3>

Chromatography is a technique used in the laboratory to physically separate two different objects and/or materials.

In chromatography, these materials are separated into two phases called the stationary phase and the movement phase.

Chromatography is also used to purify a given substance and thus determine its exact composition.

Learn more about chromatography here:

brainly.com/question/1394204

You might be interested in
4. What is the common name of the compound CaOCI,?​
Paladinen [302]

Answer:

Calcium Hypochlorite is an inorganic chemical compound with chemical formula CaOCl2. They are also called calcium oxychloride and the common name of CaOCl2 is bleching or chlorine powder.

4 0
3 years ago
Question 2 (2 points)
poizon [28]

Answer:

m_w=439.2g

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}

Thus, by plugging in the data, we obtain:

m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g

Best regards!

7 0
3 years ago
For the chemical reaction , I identify the reactant and the products .
svetlana [45]

The reactant is Mercury (II) Oxide while the products are Mercury and Oxygen separately.

This is because the reactants are typically always on the left side of the yields symbol. In this decomposition reaction, it would still be the same as at the end of the reaction, there were to products produced: Mercury and Oxygen.

Products tend to always be on the right side of the yields symbol, they're what comes out of a reaction no matter what type.

Hope this helps!

7 0
4 years ago
A solution is prepared at that is initially in nitrous acid , a weak acid with , and in sodium nitrite . Calculate the pH of the
bija089 [108]

Answer:

4.07

Explanation:

There is some info missing. I think this is the original question.

<em>A solution is prepared at 25 °C that is initially 0.057 M in nitrous acid (HNO₂), a weak acid with Ka = 4.5 × 10⁻⁴, and 0.30 M in sodium nitrite (NaNO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>

<em />

Nitrous acid is a weak acid and nitrite (coming from sodium nitrite) is its  conjugate base. Together, the form a buffer system. We can calculate its pH using the Henderson-Hasselbach equation.

pH = pKa + log [base]/[acid]

pH = -log 4.5 × 10⁻⁴ + log 0.30/0.057

pH = 4.07

7 0
3 years ago
2
Law Incorporation [45]

Answer:

(a) W

(b) X

(c) Y

Explanation:

Let's consider the following table with melting and boiling points for 4 substances.

Substance     Melting Point (°C)       Boiling Point (°C)

     W                       -7                                  60

     X                       660                              2500

     Y                        180                               1330

     Z                         115                                445

Let's consider that:

  • Below the melting point, a substance is solid.
  • Between the melting and the boiling point, a substance is liquid.
  • Above the boiling point, a substance is gas.

(a) Which substance is a gas at 100°C?

At 100 °C, W is above the boiling point

(b) Which substance is a liquid for the largest range of temperature?

The largest difference between the melting point and the boiling point is that of X: 2500 - 660 = 1840.

(c) Which substance is liquid at 1000 °C and a gas at 2000°C?​

Y is between the melting and the boiling point at 1000 °C and above the boiling point at 2000 °C.

3 0
3 years ago
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