Question

Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with ammonia NH3.
What mass of ammonium phosphate is produced by the reaction of 7.1g of phosphoric acid?

Round your answer to 2 significant digits.

Answer 1

Answer:

The weight of ammonium phosphate is 10 gm

Explanation:

The chemical reaction of ammonium phosphate formation is as follows.

$3NH_{3}+H_{3}PO_{4} \rightarrow [(NH_{4})_{3}PO_{4}]$

From the reaction one mole of phosphoric acid is equivalent to the one mole of ammonium phosphate.

So, "n" mole of phosphoric acid is equivalent to the "n" mole of ammonium phosphate.

Number of moles in 7.1 grams of phosphoric acid = $\frac{7.1}{Molarmass\,of phosphoric\,acid}$

$\frac{7.1}{98}= \frac{1}{13.8}$

Formation weight of ammonium phosphate :

Weight of ammonium phosphate = $= \frac{1}{13.8}\times Molarmass\,of\,\,ammonium\,phosphate$

$=\frac{149}{13.8} = 10.79gm$

Round the answer to 2 significant digits

Weight of ammonium phosphate = 10 gm