Answer:
Schedule:
![\left[\begin{array}{cccccc}$Period&$Beginning&$Installment&$Interest&$Amortization&$Ending\\1&113515&15700&0&15700&97815\\2&97815&15700&2934&12766&85049\\3&85049&15700&2551&13149&71900\\4&71900&15700&2157&13543&58357\\5&58357&15700&1752&13948&44409\\6&44409&15700&1333&14367&30042\\7&30042&15700&902&14798&15244\\8&15244&15700&456&15244&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccc%7D%24Period%26%24Beginning%26%24Installment%26%24Interest%26%24Amortization%26%24Ending%5C%5C1%26113515%2615700%260%2615700%2697815%5C%5C2%2697815%2615700%262934%2612766%2685049%5C%5C3%2685049%2615700%262551%2613149%2671900%5C%5C4%2671900%2615700%262157%2613543%2658357%5C%5C5%2658357%2615700%261752%2613948%2644409%5C%5C6%2644409%2615700%261333%2614367%2630042%5C%5C7%2630042%2615700%26902%2614798%2615244%5C%5C8%2615244%2615700%26456%2615244%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Journal entries:
equipment 113,515 debit
lease liablity 97,815 credit
cash 15,700 credit
--to record lease agrement and first payment.
interest expense 2,934 debit
lease liability 2,934 credit
--to record interest for the year 2021--
lease liablity 15,700 debit
cash 15,700 credit
--to record Jan 1st,2022 Payment--
Explanation:
As the payment are at the beginning there is no interest in the first period.
We record the expense for the year at Dec 31th Increasing the liability. When paying we increase decrease the liability and cash.
Answer:
the process of transforming privately owned assets into public assets by bringing them under the public ownership of a national government or state.
Explanation:
Answer:
aswer is
Explanation:
because is Hp is globally science
Answer: The distribution of sample means is:
As the sample size is more than 30 so the sampling distribution of the sample means can be said to be approximately normal with the mean equal to 10.53 hours and standard deviation equals to 0.33 hours.
Explanation:
The mean,
μ=10.53
The population standard deviation,
σ= 2
The sample size, n=36
z score:
z= (xbar −μ)/σ
The standard error:
σxbar=σ/√n
=2/√36
=0.33
The standard error represents the distribution sample mean is 0.33.
