Vertex form is f(x) = a(x - b)^2 + c where the vertex is (b, c) and a is some constant.
So for the first part we have f(x) = a(x + 6)^2 - 1
for root -9:- a( -9+6)^2 - 1 = 0
9a - 1 = 0 , a = 1/9
The other 3 are derived in the same way.
so required equation is f(x) = (1/9)(x + 6)^2 - 1
Answer:
C. Create the perpendicular bisector of FG. Then use the points of intersection of the perpendicular bisector with the circle, along with points F and G, to draw the square.
Step-by-step explanation:
The steps are below:
1. A diameter of the circle is drawn.
2. A perpendicular bisector of the diameter is drawn using the method described in the perpendicular bisector of a segment. This is also a diameter of the circle.
3. The resulting four points on the circle are the vertices of the inscribed square.
Answer:
I believe its C
Step-by-step explanation:
I added them up lol
Answer:
d. √(1/(x+1))
Step-by-step explanation:
Just as operations can be performed on numbers and variables, so can operations be performed on functions. Here, you're asked to simplify the ratio of two functions.
At this point, you're supposed to know the factoring of the difference of squares:
