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patriot [66]
3 years ago
14

A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the dista

nce was 23.74 n. The coefficient of kinetic friction between the tires and the road is μk = 0.29 How fast was the car going when the driver applied the brakes
Physics
1 answer:
sleet_krkn [62]3 years ago
3 0
<h2>The velocity of car was m m/s </h2>

Explanation:

When the car skids , its centripetal force is provided by frictional force .

Here centripetal force F = \frac{mv^2}{r}

here v is the velocity of car and r is the radius of the curve .

The frictional force f = μ R

here μ is the coefficient of kinetic friction and R is normal reaction

Thus f =  m g

On horizontal road R = mg

Thus F = f  at the time of skid .

Thus v = \sqrt{\mu rg}

= \sqrt{0.29x23.74x10} = 9 m/s

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