Solving this using the time, we know that range = horizontal velocity x time of flight
since
there are no horizontal forces acting on the ball, there are no
horizontal accelerations and the initial horizontal velocity of 36 cos
28 will be constant throughout. If we use the correct time of flight given the launch parameters, we have
range = 36 cos 28 x 3.44 s = 109.3 m
Answer:
a) 23.2 e V
b) energy of the original photon is 36.8 eV
Explanation:
given,
energy at ground level = -13.6 e V
energy at first exited state = - 3.4 e V
A photon of energy ionized from ground state and electron of energy K is released.
h ν₁ - 13.6 = K
K combine with photon in first exited state giving out photon of energy
= 26.6 e V
h c = 6.626 × 10⁻³⁴ × 3 × 10⁸ = 12400 e V A°
K + ( 3.4 ) = 26.6 e V
a) energy of free electron
K = 26.6 - 3.4 = 23.2 e V
b) energy of the original photon
h ν₁ - 13.6 = K
h ν₁ = 23.2 + 13.6
= 36.8 e V
energy of the original photon is 36.8 eV
Find refractive index first
![\\ \rm\Rrightarrow \mu=\dfrac{c}{v}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cmu%3D%5Cdfrac%7Bc%7D%7Bv%7D)
![\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cmu%3D%5Cdfrac%7B1.0003%7D%7B1.33%7D)
![\\ \rm\Rrightarrow \mu =0.75](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cmu%20%3D0.75)
Now
![\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cdfrac%7Bsini%7D%7Bsinr%7D%3D%5Cmu)
![\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cdfrac%7Bsin45%7D%7Bsinr%7D%3D0.75)
![\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cdfrac%7Bsin45%7D%7B0.75%7D%3Dsinr)
![\\ \rm\Rrightarrow sinr=0.94](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20sinr%3D0.94)
![\\ \rm\Rrightarrow r=sin^{-1}(0.94)](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20r%3Dsin%5E%7B-1%7D%280.94%29)
![\\ \rm\Rrightarrow r=70^{\circ}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20r%3D70%5E%7B%5Ccirc%7D)
This means that there is same current flow in both the circuit, or the circuit one has twice the power of circuit two.
According to ohm's law, the resistance is given as
I=V/R
Since the circuit one has twice the voltage, and resistance
I1=I2
There are two ways to find energy. Energy=F*d=mv^2. We can use this relationship to find v: