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tia_tia [17]
3 years ago
5

Determine the distance between a newly discovered planet and its single moon if the orbital period of the moon is 1.2 Earth days

and the mass of the planet it orbits is 9.38E24 kg.You may assume the orbit to be circular.
Physics
1 answer:
Vinil7 [7]3 years ago
8 0

Answer:

The distance is r = 55430496 \  m  

Explanation:

From the question we are told that

   The period of the moon T =  1.2 days = 1.2 * 24 * 3600 = 103680 \  s

    The mass of the planet is  m_p =  9.38*10^{24} kg

Generally the period of the moon is mathematically represented as

       T  =  2 *  \pi * \sqrt{ \frac{r^3 }{ G * m_p } }

Here G is the gravitational constant with value

        G  =  6.67 *10^{-11} \  N \cdot m^2/kg^2

=>   T  =  2 *  \pi * \sqrt{ \frac{r^3 }{ G * m_p } }

=>   103680   =  2 *  3.142  * \sqrt{ \frac{r^3 }{ 6.67*10^{-11} * 9.38*10^{24} } }

=>    272218492.31 = \frac{r^3}{ 6.67 *10^{-11} * 9.38*10^{24}}

=>    r = \sqrt[3]{ 1.7031241*10^{23}}j

=>   r = 55430496 \  m        

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If 90 grams of gold has a volume of 5 cm3, calculate the density (include the units and show your work or you get no credit
ehidna [41]

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Explanation:

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6 0
3 years ago
A person walks due south from point A for 500 yards and then due west for 300 yards, arriving at point B. Answer the following q
Pepsi [2]

The total displacement of the person walking from point A to point B is 300 yards.

As shown in the figure we can conclude that the required method to calculate the total displacement is the Pythagoras theorem.

<h3>Pythagoras theorem in brief :</h3>

According to the Pythagorean Theorem, the square that represents the hypotenuse, or side of a right triangle that faces the right angle, is equal to the total of the squares on the triangle's legs.(or, in popular algebraic notation, a^2 + b^2 = c^2).

<h3>Calculation: </h3>

Let,

a = 500

b=  300

Hence by using Pythagoras' theorem

Total displacement of the person = \sqrt{500^{2}  + 300^{2} } = \sqrt{900000} = 300

Thus the total displacement of the person from starting point is 300 yards.

Learn more about the displacement examples here:

brainly.com/question/11188852

#SPJ4

5 0
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