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djverab [1.8K]
3 years ago
14

In 1909, galileo first looked at the milky way using very powerful binoculars

Physics
2 answers:
pashok25 [27]3 years ago
4 0

Galileo first studied the Milky Way through his telescope in January, 1610 not 1909. Until his observations, the Milky Way was thought to be a band of wispy whitish clouds passing through the heavens. To Galileo's amazement, instead of seeing just a nebula (the Greek work for cloud) the milky wisps resolved into innumerable tiny stars, so crowded together that, without the aid of a telescope, the light from those stars simply blended together. 

Explanation:

False. Galileo died in 1642. In 1609, 300 years before your question's year, he was making a telescope. There were no binoculars in his time. He would have been gazing at the Milky Way then.

Galileo first studied the Milky Way through his telescope in January 1610. Until his comments, the Milky Way was conceived to be a band of wispy whitish clouds crawling within the heavens.


anastassius [24]3 years ago
3 0
<span>Galileo first studied the Milky Way through his telescope in January, 1610 not 1909. Until his observations, the Milky Way was thought to be a band of wispy whitish clouds passing through the heavens. To Galileo's amazement, instead of seeing just a nebula (the Greek work for cloud) the milky wisps resolved into innumerable tiny stars, so crowded together that, without the aid of a telescope, the light from those stars simply blended together. </span>
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What is the weight in Newtons of a ball with a mass of 7.77 kg?
rusak2 [61]

Answer:

76.1N

Explanation:

Given parameters:

Mass of the ball  = 7.77kg

Unknow:

Weight of balloon  = ?

Solution:

Weight is the vertical force applied on a body.

  Weight = mass x acceleration due gravity

So;

  Weight  = mass x acceleration due to gravity

So;

 Weight  = 7.77 x 9.8  = 76.1N

4 0
3 years ago
16 to 19 year old male and females are how much more likely to be involved in a crash?
Sedbober [7]
I say around 40% - 60%

https://www.dmv.ca.gov/portal/dmv/detail/teenweb/more_btn6/traffic/traffic
http://www.teendriversource.org/stats/support_teens/detail/57
http://www.rmiia.org/auto/teens/Teen_Driving_Statistics.asp

(I just corrected the question. Sorry if it is still incorrect.)
6 0
4 years ago
A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
Diano4ka-milaya [45]

solution:

As Given plane is flying in east direction.

It throws back some supplies to designated target.

Time taken by the supply to reach the target =10 seconds

g = Acceleration due to gravity = - 9.8 m/s²[Taken negative as object is falling Downwards]

As we have to find distance from the ground to plane which is given by d.

d = \frac{1}{2}\times g\times t^2

 = \frac{1}{2}\times (9.8) \times(100) =50\times 9.8=490 meters

Distance from the ground where supplies has to be land  to plane  =  Option B =490 meters

6 0
3 years ago
Read 2 more answers
When flying in an airplane, you are most likely in which layer of the atmosphere? mesosphere thermosphere stratosphere trosphere
Sergeeva-Olga [200]
Lower stratosphere, this is to avoid turbulence
6 0
3 years ago
Read 2 more answers
Hello guys! Can u please help me with physics. I translated it in English. Can yall help me please how much u can!!
DedPeter [7]

1. Since the body is thrown vertically upward, the only force acting on it as it rises and falls is gravity, which causes a constant downward acceleration with magnitude g = 9.8 m/s². Because this acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where

u = initial speed

v = final speed

a = acceleration

∆x = displacement

At its maximum height, some distance y above the point where the body is launched, the body has zero velocity, so

0² - (20 m/s)² = 2 (-9.8 m/s²) y

Solve for y :

y = (20 m/s)² / (2 (9.8 m/s²)) ≈ 20.4 m

2. Relative to the ground, the body's maximum height is 60 m + 20.4 m ≈ 80.4 m.

3. At any time t ≥ 0, the body's vertical velocity is given by

v = 20 m/s - gt

At the highest point, we have

0 = 20 m/s - (9.8 m/s²) t

and solving for t gives

t = (20 m/s) / (9.8 m/s²) ≈ 2.04 s

4. The body's height y above the ground at any time t ≥ 0 is given by

y = 60 m + (20 m/s) t - 1/2 gt²

Solve for t when y = 0 :

0 = 60 m + (20 m/s) t - 1/2 (9.8 m/s²) t²

Using the quadratic formula,

t = (-b + √(b² - 4ac)) / (2a)

(and omitting the negative root, which gives a negative solution) where a = -1/2 (9.8 m/s²), b = 20 m/s, and c = 60 m. You should end up with

t ≈ 6.09 s

5. At the time found in (4), the body's velocity is

v = 20 m/s - g (6.09 s) ≈ -39.7 m/s

Speed is the magnitude of velocity, so the speed in question is 39.7 m/s.

6 0
3 years ago
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