1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
8090 [49]
3 years ago
14

A straight trail with a uniform inclination of 15 degrees leads from a lodge at an elevation of 600 feet to a mountain lake at a

n elevation of 6100 feet. What is the length of the trail (to the nearest foot)

Physics
1 answer:
9966 [12]3 years ago
7 0

Answer:

The length of the trail = 22796 ft

Explanation:

From the ΔABC

AC = length of the trail = x

AB = 6100 - 600 = 5500 ft

Angle of inclination \theta = 15°

\sin \theta = \frac{AB}{AC}

\sin 15 = \frac{5900}{x}

x = \frac{5900}{0.2588}

x = 22796 ft

Since x = AC = Length of the trail.

Therefore the length of the trail = 22796 ft

You might be interested in
An ac generator with Em = 223 V and operating at 399 Hz causes oscillations in a series RLC circuit having R = 222 Ω, L = 147 mH
Doss [256]

Answer:

Xc= 17.267 Ω,   Z= 415.5 Ω,   I= 0.537 A

Explanation:

Em = 223 V

f= 300 Hz, R = 222 Ω, L = 147 mH,  C = 23.1 μF

a)

Capacitive reactance = Xc=?

Xc= \frac{1}{2\pi fC}

Xc=1/2pi *399*23.1*10^-6

Xc= 17.267 Ω

b).

Z=\sqrt{ R^2 + (Xl - Xc)^2}

Xl= 2π * f * L  

Xl= 2π * 399 * 147 * 10^{-3}

Xl= 368.5 Ω

Z=\sqrt{ R^2 + (Xl - Xc)^2} = \sqrt{222^2 + (368.5 - 17.267)^2}

Z= 415.5 Ω  

c).

Current:

I= V / Z= Em / Z

I= 223/415.5

I= 0.537 A

3 0
3 years ago
Please Help! Multiple Choice!
attashe74 [19]
Option A 3......
... ........
8 0
2 years ago
Where is this earthquake's epicenter?
Studentka2010 [4]
The correct answer is C
4 0
3 years ago
Read 2 more answers
When the ball of the pendulum moves from (x) to (y) in a duration of 0.02 sec the frequency equals
Mariulka [41]
0.4 sec the frequency equals
5 0
1 year ago
A mechanic jacks up the front of a car to an angle of 8.0° with the horizontal in order to change the front tires. the car is 3.
SOVA2 [1]
<span>First draw a free-body diagram. Torque T = Force F x Distance d where force is the component of gravitational force g and d is the lever arm distance to the pivot point. Since the pivot point is at the back tire we subtract that from the length of the car resulting in d = 1.12 - 0.40 = 0.72 meters = d. We are interested in the perpendicular component of the force exerted on the car jack so use sin 8 degrees then T=1130 kg x 9.81 m/s^2 x sin(8 degrees) x0.72 m = 1,110.80 Newton-meters</span>
7 0
3 years ago
Other questions:
  • You travel in a car 30 miles north to ava and home again. what is your distance? __________________________________________ what
    7·1 answer
  • How many significant figures are in the measurement 230kg
    7·1 answer
  • .What​ ​is​ ​the​ ​momentum​ ​of​ ​a​ ​car​ ​with​ ​a​ ​mass​ ​of​ ​1,300​ ​kg​ ​traveling​ ​north​ ​at​ ​a​ ​speed​ ​of 28​ ​m/
    9·1 answer
  • Find the magnitude &amp; direction: 50N 25 N 35 N 10N
    14·1 answer
  • Calculate the total number of Cl atoms in 150mL of liquid Ccl4 (d=1.589g/mL)<br>​
    10·1 answer
  • What is the main limitation of debye huckel theory​
    6·1 answer
  • A roller coaster is stationary at the top of a ramp.
    6·1 answer
  • If a 2 kg object is falling at 3 m/s at what rate is gravity working on the object
    9·1 answer
  • It is made up of small particles
    5·2 answers
  • ox A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!