PLEASE ANSWER ASAP I REALLY NEED HELP!!!!!!

Physics

1 answer:

Andrews [41]3 years ago

4 0

Answer:

In thermodynamics, heat is transferred energy that moves between substances or systems because of their temperature difference. According to the first law of thermodynamic and the law of energy conversion s a form of energy, heat is cannot be created or destroyed only moves from one form to other.

The stone gets heat energy from fire and moves this heat energy or thermal energy to water as it cools off and the water warms up. Heat moves or is transferred spontaneously from the hot stone into the cold water. Eventually, the stone and water have the same temperature and water becomes heated. At the time of heat flowing out of the stone into the water, the heat energy became less ordered, due to spreading out through both the stone and the water. This is a net increase in entropy which is the second law of entropy.

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The gravitational force between two objects is f. If masses of both objects are halved without changing distance between them, t

Marrrta [24]

The gravitation force is quartered when two objects' masses are halved without changing their distance.

Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

F=(KM1 M2)/r^2

K= Gravitation force constant

M1M2 = masses of the object

r = distance between objects

When M1 and M2 are halved, it becomes M1/2 and M2/2

F=(K M1/2 x M2/2)/r^2

F=(K (M1 x M2)/4)/r^2

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Recall

F=(KM1 x M2)/r^2

Therefore

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Saturn moves in an orbit around the Sun with radius 10 AU. How many degrees does it move on the Celestial in one year? (Hint: Ca

Lana71 [14]

Answer:

B. About 12 degrees

Explanation:

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Now, we don't actually need to solve the values of the constants, since we now that the distance from the sun to Saturn is 10 times the distance from the sun to the earth. We now this because 1 AU is the distance from the earth to the sun.

Now, we divide the expression used to calculate the orbital period of Saturn by the expression used to calculate the orbital period of the earth. Notice that the constants will cancel and we will get the rate of orbital periods in terms of the distances to the sun:

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