Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
Answer:
the formula is VAT %op cp ×13500 do that using this formul6 is should correct
It would be 179,000. You just multiply them together.
We need to know the function that models the difference in the number of customers visiting the two stores.
We know the function that models the number of customers in the cafeteria
W (x) = 0.002x3 - 0.01x2
We also know the function that models the number of customers who visit the ice cream parlor
R (x) = x2 - 4x + 13
Therefore the difference, D (x), in the number of customers visiting the two stores is:
D (x) = W (x) - R (x)
D (x) = 0.002x ^ 3 - 0.01x ^ 2 - (x ^ 2 -4x +13)
D (x) = 0.002x ^ 3 - 0.01x ^ 2 - x ^ 2 + 4x -13
D (x) = 0.002x ^ 3 - 1.01x ^ 2 + 4x -13
<span> The answer is the third option</span>
No.
The ratio of the areas is the ratio of the squares of the scale factor.
So it's 2^2 : 5^2 = 4:25
