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svetlana [45]
3 years ago
7

10 1/8 + (3 5/8 + 2 7/8)

Mathematics
2 answers:
Ghella [55]3 years ago
8 0
10 1/8 + (3 5/8 + 2 7/8) =
10 1/8 + (6 4/8) = 16 5/8
erik [133]3 years ago
3 0
If you're trying to simplify, 3 5/8+ 2 7/8 = 6 4/8. So 10 1/8 + 6 4/8 is 16 5/8
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Anna11 [10]

Answer:

1/3 of 6 meters is 2 meters

Step-by-step explanation:

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1,-4,-9,-14,-19 what’s the 5th term
wlad13 [49]

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Step-by-step explanation:

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
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VashaNatasha [74]
It would be 9.54x10^6 because the nine is 6 spaces away from the decimal point if you get what i mean.
8 0
2 years ago
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Which compound inequality could this graph be the solution of?
vodomira [7]

-4 ≤ x ≤ 6

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A. 3x + 14 ≥ 2 and 1 - x ≥ -5

4 0
2 years ago
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