Question

A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0 m/s, and the distance from the limb to the saddle is 3.00 m. What must be the horizontal distance between the saddle and limb when the ranch hand makes his move?

Answer 1

Answer:

D = 7.82 m

Explanation:

given,

speed of horse = 10 m/s

vertical distance between the saddle and limb = 3 m

horizontal distance = ?

Calculation of time taken to cover the vertical distance.

using equation of motion

$s = u t + \dfrac{1}{2}at^2$

initial velocity = 0 m/s

$s = 0+ \dfrac{1}{2}at^2$

$t = \sqrt{\dfrac{2s}{a}}$

$t = \sqrt{\dfrac{2\times 3}{9.8}}$

t = 0.782 m

horizontal distance covered in this time

D = v t

D = 10 x 0.782

D = 7.82 m

Horizontal distance covered is equal to 7.82 m.