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kaheart [24]
3 years ago
6

A capacitor with the capacitance constant C has a charge of Q and a potential difference of V.

Physics
1 answer:
valina [46]3 years ago
7 0

the new capacitance is 2c

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A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill. there is no friction, what is
HACTEHA [7]

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Explanation:

Given;

mass of the person in cart, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

acceleration due to gravity, g = 9.8 m/s²

final speed of the cart before it goes up the hill, v = 19 m/s

Apply the principle of conservation of energy;

mgh_{max} = \frac{1}{2}mv^2_{max}\\\\ gh_{max} = \frac{1}{2}v^2_{max}\\\\h_{max} = \frac{v^2_{max}}{2g} \\\\h_{max} =\frac{(19)^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

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3 years ago
Which is an example of qualitative data?
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The answer is C)the rating that the golfers give Callaway clubs
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2 years ago
A generator produces 60 A of current at 120 V. The voltage is usually stepped up to 4500 V by a transformer and transmitted thro
aalyn [17]

Answer:

The percentage power lost in the transmission line if the voltage not stepped up is 50%.

Explanation:

Given that,

Current = 60 A

Voltage = 120 V

Resistance = 1.0 ohm

We need to calculate the power

Using formula of power

P=I\times V

Where,I =current

V = voltage

Put the value into the formula

P=60\times120

P=7200\ W

We need to calculate the percentage power lost in the transmission line

If the voltage is not stepped up

Then, the power loss

P'=I^2\times R

Put the value into the formula

P'=(60)^2\times1

P'=3600\ W

The percentage power loss P''

P''=\dfrac{P'}{P}\times100=\dfrac{3600}{7200}\times100

P''=50\%

Hence, The percentage power lost in the transmission line if the voltage not stepped up is 50%.

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