Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
<u>Explanation:</u>
Given;
Number of turns, N = 1000
Inner radius, r₁ = 1cm
Outer radius, r₂ = 2cm
Current, I = 1.5A
Magnetic field strength, B = ?
The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr
where,
a < r < b and a and b are the inner and outer radii of the toroid.
The magnetic field of toroid is
Substituting the values in the formula:
Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT
That's what happens if there is more than one force acting on the
object, and the forces are balanced, that is, they all "cancel out".
Think of the rope in a Tug-'o-War. It has 50 musclebound football guys
all pulling the rope to the west, and 150 strong cheerleaders all pulling
the rope to the east. The total force to the west is exactly equal to the
total force to the east, and the rope doesn't move at all. The forces on it
are balanced, and the effect on its motion is the same as if there were
no force on it at all.
Answer:
W = 28226.88 N
Explanation:
Given,
Mass of the satellite, m = 5832 Kg
Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m
The time period of the orbit, T = 1.9 h
= 6840 s
The radius of the planet, R = 4.38 x 10⁶ m
The time period of the satellite is given by the formula
second
Squaring the terms and solving it for 'g'
g = 4 π² 
m/s²
Substituting the values in the above equation
g = 4 π² 
g = 4.84 m/s²
Therefore, the weight
w = m x g newton
= 5832 Kg x 4.84 m/s²
= 28226.88 N
Hence, the weight of the satellite at the surface, W = 28226.88 N
Care este problema? Btw why are you speaking Romanian
That is a lunar eclipse. At night, when the Earth is between the Sun and the moon, the moon would appear to be red. Just for future reference, a solar eclipse is when the Moon is between the Sun and Earth. Speaking of which, check out the solar eclipse this August!
