Question 8

The diameter of an automobile tire is closest to

slamgirl [31]

Answer:

(1) 10^−2 m

Explanation:

The diameter of the tire of an automobile is generally expressed in centimetres; we can say that the diameter of a tire is generally about

d = 20 cm (20 centimetres)

Now we have to verify which option is closest to this value. To do that, we have to keep in mind the equivalence between metres and centimetres; in fact, we have:

$1 cm = 10^{-2} m$

This means that we can rewrite the diameter of the tire of a car as

$d=20 cm = 20\cdot 10^{-2} m$

By comparing it with the given options, we see that the closest option is

(1) 10^−2 m

which is therefore the correct answer.

6 0

4 years ago

How much work would be needed to lift the ball from the 2-m shelf to the 5-m shelf, and how much potential energy would it have

Stells [14]

Answer:

a) 2.94 N

b) 4.90 N

Explanation:

Let us assume that the weight of the ball is 0.98 N

Solution:

a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:

Potential energy = weight (w) * height (h)

PE = wh

Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N

Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N

b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

6 0

3 years ago

Margaret is the new director of research at a well-known pharmaceutical company. She has been asked to design a set of research

Serjik [45]

Answer:

Double blind experiment

Explanation:

It is an experimental method , which helps to avoid any impartiality and any error due to biasing .

The experiment give rise to very accurate results , which is very important for any experiment .

Hence , the new director Margaret , need to design a set of double - blind experiments.

7 0

4 years ago

Find the height or length of these natural wonders in km, m, and cm.A. A cave system with a mapped length of 354 miles.B. A wate

cricket20 [7]

Explanation:

Some standard unit conversion are 1 mile = 1.609344 km, 1 ft.= 30.48 cm,

1 km= 1000 m or 1 m = 0.001 km and 1 m= 100 cm or 1 cm=0.01 m.

Now, use these values to convert the given lengths.

A. length of cave = 5 miles (given)

From standard value 1 mile = 1.609344 km

$\Rightarrow$ 5 miles = $\times$ 1.609344 km= 8.04672 km,

$\Rightarrow$ 5 miles =8.04672 $\times$ 1000 m= 8046.72 m [ as 1 km = 1000 m]

$\Rightarrow$ 5 miles = 8046.72 $\times$ 100 cm=804672 cm

B. Height of the waterfall = 1235 ft. (given)

1 ft.= 30.48 cm [ from standard value]

$\Rightarrow$ 1235.2 ft.= 1235.2 $\times$ 30.48 cm=37648.896 cm,

$\Rightarrow$ 1235.2 ft.=37648.896 $\times$ 0.01 m =376.48896 m [ as 1 cm = 0.01 m]

$\Rightarrow$ 1235.2 ft.=376.48896 $\times$ 0.001 km =0.37648896 km [ as 1 m = 0.001 km]

C. Height of the mountain= 21320 ft. (given)

From standard value: 1 ft.= 30.48 cm

$\Rightarrow$ 21320 ft.= 21320 $\times$ 30.48 cm=649833.6 cm,

$\Rightarrow$ 21320 ft.=649833.6 $\times$ 0.01 m =6498.336 m [ as 1 cm = 0.01 m]

$\Rightarrow$ 21320 ft.=6498.336 $\times$ 0.001 km =6.498336 km [ as 1 m = 0.001 km].

D. Depth of canyon =6630 ft.

From standard value: 1 ft.= 30.48 cm

$\Rightarrow$ 6630 ft.= 6630 $\times$ 30.48 cm=202082.4 cm,

$\Rightarrow$ 6630 ft.=202082.4 $\times$ 0.01 m =2020.824 m [ as 1 cm = 0.01 m]

$\Rightarrow$ 6630 ft.=2020.824 $\times$ 0.001 km =2.020824 km [ as 1 m = 0.001 km].

4 0

4 years ago

When the north pole of a bar magnet is moved into a solenoid, the needle on a galvanometer attached to the solenoid moves to the

djyliett [7]

answer BBBBBBBBBBBB on EDGE

4 0

3 years ago

Read 2 more answers