Assume a 100-m tape measures 3 mm too short. Five measurements of a distance give results of 253.294, 253.287, 253.289, 253.284,
253.297 m, respectively. Compute (show details) the following statistical quantities:
i) Mean
ii) Median
iii) Residuals
iv) Standard Deviation
Points only awarded to answers that use LaTeX and that show clear and concise step by step solutions that justify each step.
i) Mean
ii) Median
iii) Residuals
iv) Standard Deviation
Points only awarded to answers that use LaTeX and that show clear and concise step by step solutions that justify each step.
1 answer:
You might be interested in
Answer:
5.7058kj/mole
Explanation:
Please see attachment for step by step guide
Answer: 3/2mg
Explanation:
Express the moment equation about point B
MB = (M K)B
-mg cosθ (L/6) = m[α(L/6)](L/6) – (1/12mL^2 )α
α = 3g/2L cosθ
express the force equation along n and t axes.
Ft = m (aG)t
mg cosθ – Bt = m [(3g/2L cos) (L/6)]
Bt = ¾ mg cosθ
Fn = m (aG)n
Bn -mgsinθ = m[ω^2 (L/6)]
Bn =1/6 mω^2 L + mgsinθ
Calculate the angular velocity of the rod
ω = √(3g/L sinθ)
when θ = 90°, calculate the values of Bt and Bn
Bt =3/4 mg cos90°
= 0
Bn =1/6m (3g/L)(L) + mg sin (9o°)
= 3/2mg
Hence, the reactive force at A is,
FA = √(02 +(3/2mg)^2
= 3/2 mg
The magnitude of the reactive force exerted on it by pin B when θ = 90° is 3/2mg
