How did you post this pic?
Answer:
C
Explanation:
Spontaneous combustion is a type of combustion which occurs by self-heating (increase in temperature due to exothermic internal reactions), followed by thermal runaway (self-heating which rapidly accelerates to high temperatures) and finally, ignition.
Mass of the bullet (m) = 8.13 g = 0.00813 kg
velocity of the bullet (v) = 1337 miles/hr
The de Broglie wavelength (∧) of an object of mass (m) travelling at a velocity (v) is given as:
∧ = h/m*v
where h = Planck's constant = 6.626 *10^-34 kgm2/s
Convert velocity from miles/hr to m/s
1 mile/hr = 0.447 m/s
1337 miles/hr = 0.447*1337 = 597.64 m/s
∧ = 6.626*10^-34 m2.Kg.s-1/0.00813 kg * 597.64 ms-1
∧ = 1.363*10^-34 m
The given chemical equation is:
On balancing the equation we get,
Calculating enthalpy of formation of this reaction from the standard heats of formation of the products and reactants:
Δ![H_{reaction}^{0}=[H_{f}^{0}(Al_{2}O_{3}(s)) + (3*H_{f}^{0}(H_{2}SO_{4}(aq))] - [H_{f}^{0}(Al_{2}SO_{4}(aq)) + (3*H_{f}^{0}(H_{2}O(l))]](https://tex.z-dn.net/?f=H_%7Breaction%7D%5E%7B0%7D%3C%2Fp%3E%3Cp%3E%3D%5BH_%7Bf%7D%5E%7B0%7D%28Al_%7B2%7DO_%7B3%7D%28s%29%29%20%2B%20%283%2AH_%7Bf%7D%5E%7B0%7D%28H_%7B2%7DSO_%7B4%7D%28aq%29%29%5D%20-%20%20%20%5BH_%7Bf%7D%5E%7B0%7D%28Al_%7B2%7DSO_%7B4%7D%28aq%29%29%20%2B%20%283%2AH_%7Bf%7D%5E%7B0%7D%28H_%7B2%7DO%28l%29%29%5D)
=[(-1669.8kJ/mol)+ {3* (-909.27 kJ/mol)}]-[(-3442kJ/mol)+{3*(-285.8 kJ/mol)}]
=[(-4397.61kJ/mol)]-[(-4299.4kJ/mol)]
=-98.21kJ/mol
Total enthalpy change when 15 mol of 
reacts will be=
