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3 years ago

Consider the polynomial p(x)=8x3+12x2+2x+3.

Mathematics

1 answer:

Ivahew [28]3 years ago

3 0

A: $(4x^2+1)(2x+3)$

B: grouping

Step-by-step explanation:

We are given the polynomial: $p(x)=8x^3+12x^2+2x+3$

Part A: What is the correct factorization of $p(x)=8x^3+12x^2+2x+3$ over the integers?

We need to factorize the term $p(x)=8x^3+12x^2+2x+3$

Factorizing by grouping:

$p(x)=8x^3+12x^2+2x+3$

$p(x)=(8x^3+12x^2)+(2x+3)$

$p(x)=4x^2(2x+3)+1(2x+3)$

$p(x)=(4x^2+1)(2x+3)$

So, factors of the term $p(x)=8x^3+12x^2+2x+3$ are $p(x)=(4x^2+1)(2x+3)$

Part B: What method is used to factor p(x)=8x3+12x2+2x+3?

The method used to factor the given polynomial is grouping.

We group the terms and then find the common terms in that specific group

So, the answers are:

A: $(4x^2+1)(2x+3)$

B: grouping

Keywords: Finding Factors

Learn more about finding factors at:

#learnwithBrainly

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We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
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