The answer is r have a good day
Answer:
Step-by-step explanation:
From your characteristic equation, your recursive equation is

the general solution:

The initial conditions are

For f(0) = 1, that is

For f(1) = 3, that is


From (*) and (**) you solve for A and B
you have A = 4/7 and B= 3/7
Replace A, B into the general one, you have the particular solution for the given condition

<span><span>K = k + 13</span><span>78</span></span>
Cross multiply:
K * 8 = 7 * k + 13
Simplifying
K * 8 = 7 * k + 13
Reorder the terms for easier multiplication:
8K = 7 * k + 13
Reorder the terms:
8K = 7 * 13 + k
8K = 13 * 7 + k * 7
8K = 91 + 7k
Solving
8K = 91 + 7k
Solving for variable 'K'.
Move all terms containing K to the left, all other terms to the right.
Divide each side by '8'.
K = 11.375 + 0.875k
Simplifying
K = 11.375 + 0.875k
there it was hard but i got it
To solve this we just need a polynomial where the roots can be -10 so in (x -/+ N)
The Ns must equal -10
We also know there must be at least a degree of 2 or higher, so we want X^3 or 3 roots. Given this we can construct our function;
H(x) = (X-2)(X+5)(X+1)
1*5*-2 = -10
So multiplying that out to get the standard form
X^2-2X+5X-10(X+1)
Simplifying to X^2 +3X-10(X+1)
X^3+3X^2-10X + X^2 +3X -10
Which simplifies to:
X^3+4X^2-7X-10
And below the desmos shows the y-int at (0,-10)
To find distance between points <span>A(<span>xA</span>,<span>yA</span>)</span> and <span>B(<span>xB</span>,<span>yB</span>)</span>,
formula:
<span>d(A,B)=</span>√ [(xB−xA)^2+(yB−yA)^2]
so distance between the points: (–6, 7) and (–1, –5)<span>
</span>= √ [<span><span><span><span>(<span>−1−<span>(<span>−6</span>)</span></span>)^</span>2 </span>+ <span><span>(<span>−5−7</span>)^</span>2]
</span></span>= </span>√ (<span><span>25+144)
</span>= </span>√ 169
<span><span><span>= </span></span><span>13
answer
13</span></span>