Answer:
a = 6.53 m/s^2
v = 11.5689 m/s
Explanation:
Given data:
engine power is 217 hp
70 % power reached to wheel
total mass ( car + driver) is 1530 kg
from the data given
2/3 rd of weight is over the wheel
w = 2/3rd mg
maximum force
we know that F = ma
the new power is 
solving for speed v
![v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}](https://tex.z-dn.net/?f=v%20%3D%200.7%20%5Cfrac%7B217%20%5B%5Cfrac%7B746%20w%7D%7B1%20hp%7D%5D%7D%7B1500%20%5Ctimes%206.53%7D)
v = 11.5689 m/s
Answer:
normal force, the pluck will move off in a different direction
Explanation:
As it is outside the focal point it must be real.Real images must be inverted.
As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size.
Hope this helps you :)
The integral of acceleration is velocity. The area under the curve is an integral. You can see the relation here. So just take the area under those time intervals. I’m assuming 1.7 is where it crosses the x-axis
For the first interval:
Base = 1.7
Height = -2
[1.7*(-2)]/2 = -1.7 cm/s
For the second interval:
There are two triangles and a rectangle here.
Base #1 = 0.3
Height #1 = 1
Base #2 = 1
Height #2 = 1
Length = 3
Width = 1
Apply the area formulas to get an answer of 3.65 cm/s
