1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lyrx [107]
3 years ago
5

A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi

s. Just before the collision, one ball, of mass 3.0 kg, is moving upward at 20 m/s and the other ball, of mass 2.0 kg, is moving downward at 12 m/s. How high do the combined two balls of putty rise above the collision point?
Physics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

h = 2.64 meters      

Explanation:

It is given that,

Mass of one ball, m_1=3\ kg

Speed of the first ball, v_1=20\ m/s (upward)

Mass of the other ball, m_2=2\ kg

Speed of the other ball, v_2=-12\ m/s (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}

V=\dfrac{3\times 20+2\times (-12)}{3+2}

V = 7.2 m/s

Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :

mgh=\dfrac{1}{2}mV^2

h=\dfrac{V^2}{2g}

h=\dfrac{7.2^2}{2\times 9.8}

h = 2.64 meters

So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.

You might be interested in
As shown in the video, earth has two tidal bulges at all times. approximately where are these bulges located?
Pepsi [2]
Tidal bulges are always on the opposite side of the Earth.
They are created because of the gravitational influence of the Moon on Earth and inertial's counter balance.

The side of the Earth that is facing the Moon is the closest to the Moon, and the gravitational force is the strongest when the distance is the smallest.  

As the Moon is trying to draw the water towards itself, the inertia tries to keep the water at its place. On the opposite side of the Earth, "behind the Moon",  the gravitational force of the Moon is the weakest, so inertia is the strongest. That's why tidal bulges are at the opposite side. 
4 0
4 years ago
What does the term wavelength refer to?
Andru [333]
Are you asking what it means?

4 0
3 years ago
until a train is a safe distance from the station, it must travel at 5 m/s. once the train is on open track, it can speed up to
MatroZZZ [7]

Answer:

5 meters per second squared

Explanation:

We calculate the acceleration using the formula:

a = (vf - vi) / t

where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.

In our case:

a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2

4 0
4 years ago
A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.4 A runs through the wire
Deffense [45]

Answer:

\vec{F}=0.40176 N \hat{k}

Explanation:

To calculate the force we need to use this equation

\vec{F}=\int\limits^L_0 {i(\vec{dl}\times\vec{B})}

where L is the total length of the wire

So in this case the small element of current is

\vec{dl} = dx \hat{i}

Because x is the direction of the current flow.

As is said in the problem B is such that

\vec{B} = B \hat{j} = 0.62\hat{j} [ T]

so to use the equation above we first calculate the following cross product:

\vec{dl}\times\vec{B}=dx \hat{i}\times B \hat{j} = Bdx\hat{k}

so the force:

F = \int\limits^L_0 {i(\vec{dl}\times\vec{B})}=\int\limits^L_0{iBdx\hat{k}}

So here we use the fact that B=0 in any point of the x axis that is not x^{'}=0.27 [m], that means that we only need to do the integration between a very short distant behind the point x^{'}=0.27 [m] and a very short distant after that point, meaning:

\vec{F}= \lim_{h \to 0}{\int\limits^{x^{'}+h}_{x^{'}-h}{iBdx\hat{k}} }

so is the same as evaluating iBx at x=x^{'}

that is:

2,4 A * 0,62 T * 0,27 m \hat{k}

2,4 A * 0,62 (\frac{Kg}{A s^{2}}) * 0,27 m \hat{k}

2,4*0,62*2,7 ( \frac{ kgm }{ s^{2} } ) \hat{k}

\vec{F}=0.40176 N \hat{k}

5 0
3 years ago
The fed can attempt to decrease the federal funds rate by
Nataliya [291]

Answer:

purchasing bonds in order to increase the money supply.

Explanation:

The Federal Reserve raises or lowers interest rates through its regularly scheduled Federal Open Market Committee. That's the monetary policy arm of the Federal Reserve Banking System.

The Fed can attempt to increase the federal funds rate by selling Treasury​ bills, which decreases bank reserves.

4 0
3 years ago
Other questions:
  • Why are negative ions usually larger than positive ions
    5·2 answers
  • The moon is in a nearly circular orbit of radius r = 384000000 meters
    5·1 answer
  • Which expression should appear in the blue box to compute percent error? Accepted value – Experimental value Accepted value × Ex
    6·1 answer
  • what conclusions can be made based on the temperature of soil when the light hits the soil at 0 degrees 45 degrees and 90° angle
    7·2 answers
  • A lightbulb has a resistance of 195 ohms and carries a current of 0.62 A. The power rating of the lightbulb, to the nearest whol
    7·1 answer
  • Hydrogen is a gas at room temperature, but diamond is a solid with a high melting point.
    10·1 answer
  • Anions are formed by what
    14·2 answers
  • What can have an impact on your values?
    11·1 answer
  • Isaac attempts to kick a field goal from the 40 yard line. He kicks the football at 38 m/s at a 50° angle above horizontal. If t
    8·1 answer
  • A computer monitor has a power rating of 0.240 kw?​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!