<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B90%7D%20" id="TexFormula1" title=" \sqrt{90} " alt=" \sqrt{90} " align="absmiddle

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Irina-Kira [14]

3 years ago

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Mathematics

2 answers:

DaniilM [7]3 years ago

8 0

Answer:

$3\sqrt{10}$

Step-by-step explanation:

$\sqrt{90}$ For now, ignore the square root and focus on number inside

Can the number be divided by a perfect square

If No, the number simplified
If Yes, the number isn't simplified

90 can be divided by 9. 9 is $3^{2}$ so we put 3 on the outside of the square root sign. 10 can only be divided by 1, 2, 5, and 10...None of which are perfect squares. 10 stays inside while 3 is on the outside and it is simplified.

Gwar [14]3 years ago

8 0

Answer:

3/10

Step-by-step explanation:

because break 90 down thats 10 and 9 break 9 down its

3 and 3 which are your PAIRS break down down you get 5 and 2 and you do 5 x 2 which is 10 so you have 3/10

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The sum of three consective even integers if the largest number is y

coldgirl [10]

Step-by-step explanation:

If y is largest number, you want y, and the two next smaller even integers smaller than y - i.e. y, y-2, and y-4

The sum of these is y + (y-2) + (y-4).

This simplifies to 3y - 6 or 3(y - 2)

Since we don’t know what y is, this is as far as we can solve the problem.

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2 years ago

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EastWind [94]

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3 years ago

In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p

sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

$_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}$

We know that formula for permutations is given as

$_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}$

On substituting the given values in the formula we get,

${_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}$

$=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\
\\
=35\cdot 34\cdot 33=39270$

Therefore, there are 39270 ways in which prizes can be awarded.

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3 years ago

If U=pi(r+h),find r when U=16 1/2 and h=2<br> solve this question by take the value of pi 22/7

I am Lyosha [343]

$U=\pi (r+h) \\\\ 16 \frac{1}{2}= \frac{22}{7}\cdot (r+2) \\\\ \frac{33}{2} : \frac{22}{7}=r+2 \\\\ \frac{\not 33}{2}\cdot \frac{7}{\not 22}=r+2 \\\\ \frac{3}{2} \cdot \frac{7}{2}=r+2 \\\\ \frac{21}{4}=r^{(4}+2^{(4} \\\\ 21=4r+8 \\\\ 4r=21-8 \\\\ 4r=13 \\\\ \boxed{r=\frac{13}{4}}$

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3 years ago

EVALUATE THE FOLLOWING EXPRESSION <br> 6-2+4-8

Nikitich [7]

6-2+4-8 = 4+4-8 = 8-8 = 0

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4 years ago