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2 years ago

HELP PLS ASAPPPPPPPPPPPPPP

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

5 0

Answer: Wouldn't the answer be A?

Step-by-step explanation:

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Simplify the following

irga5000 [103]

$\huge\fbox{Answer ☘}$

$\bold\blue{( - 8z) {}^{2} } \\\bold{ = > 64z {}^{2} }$

hope helpful~

8 0

2 years ago

Maya designed two intersecting roads. She drew the roads so that one of the angles at the intersection was 45 degrees. What are

Citrus2011 [14]

The sum of opposite angles are equal, so two of the angles are 45°. The sum of all angles about the intersection of two lines is 360°. So the remaining two angles are found by:

α=(360-2*45)/2

α=135° thus all four angles are:

45°,135°,45°,135°

4 0

3 years ago

I have a question on math homework, anybody have an answer?<br> 11.5-3y=-48.5

tatyana61 [14]

Y=17.8 Please let me know if it is correct :)

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3 years ago

Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta

omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

6 0

3 years ago

While setting up a fireworks display, you have a tool at the top of the

atroni [7]

Answer:

0.79 sec

Step-by-step explanation:

Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .

$h(t)=-16t^{2} +h_{0}$

where $h_{0} =10 feet$

We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.

Let this be done at time t

h(t) = 0

$-16t^{2} +10=0$

$t^{2} =\frac{10}{16}$

$t=\frac{\sqrt{10} }{4}$

t = 0.79 sec

Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.

8 0

3 years ago