Answer:
Mass of iodine = 1954.26 g
Explanation:
Given data:
Mass of chlorine react = 546 g
Mass of iodine produced = ?
Solution:
Chemical equation:
2NaI + Cl₂ → 2NaCl + I₂
Number of moles of chlorine:
Number of moles = mass/molar mass
Number of moles = 546 g/71 g/mol
Number of moles = 7.7 mol
Now we will compare the moles of chlorine with iodine.
Cl₂ : I₂
1 : 1
7.7 : 7.7
Mass of iodine:
Mass = number of moles × molar mass
Mass = 7.7 mol × 253.8 g/mol
Mass = 1954.26 g
Answer:electrons will be equally attracted to both
Explanation:
e2020
Answer:
The moles of sucrose that are available for this reaction is 0.0292 moles
Explanation:
Combustion is an specifyc reaction where the reactants react with O₂ in order to produce CO₂ and H₂O
This combustion is: C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O
We have to conver the mass to moles, to find out the limiting reactant
10 g . 1 mol / 342 g = 0.0292 moles of sucrose
8 g . 1mol / 32g = 0.250 moles of O₂
The moles of sucrose that are available for this reaction is 0.0292 moles
Before we start to work with the equation we must find the limiting reactant. When you find it, you can do all the calculations.
Answer:
1.26x10^25 atoms of hydrogen
Explanation:
because there are 12 atoms of hydrogen in a molecule of glucose, multiply 12 by Avogadro's number (6.02x10^23) to get how many molecules of hydrogen there are in a mole of glucose. Then multiply that number by 1.75, which is the number of moles of glucose there is in this problem.
