Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴
∵ DE : CD = 5 : 3
∴
∴ KD = 5/3 KC
∵ KE = KC + 8
∵
∴
∴
∴
∴
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17
Answer:
A) By using the Pythagorean Theorem, we will see that . If we simplify it, we will find that the hypotenuse of Δ
B) approximately
Step-by-step explanation:
A) In all honesty, you don't really need to look at ΔACD at all for this one. Just use the Pythagorean Theorem (like previously stated) and solve!
***Pythagorean Theorem is
B) Here, you can also use the Pythagorean Theorem! However this time, the equation will be, .
Hope you do well on the rest of your math problems :D