All categories

3 years ago

Which functional group is found in methanol?

Chemistry

2 answers:

denis23 [38]3 years ago

8 0

Yes , CH3OH - this is methanol

egoroff_w [7]3 years ago

8 0

Answer: Option (c) is the correct answer.

Explanation:

In order to know the functional group present in a molecule the suffix at the end helps in determining it.

Hence, in methanol suffix is 'ol'.

Therefore, the functional group present in methanol is the hydroxyl group, that is, OH group is present.

Thus, we can conclude that functional group is found in methanol is -OH.

You might be interested in

Why does the total volume of water and alcohol decrease when the liquids were mixed together?

WARRIOR [948]

Answer: I think the alcohol molecules slip between the water molecules and take up that space, so you have less that you started with.

Explanation:

6 0

3 years ago

Read 2 more answers

which statement best describes the equation caco3 2hcl → cacl2 co2 h2o? caco3 is a reactant; it is present before the reaction o

fomenos

Answer: $CaCO_3$ is a reactant; it is present before the reaction occurs.

Explanation:

In a chemical reaction the chemical formulas written before the arrow are described as reactants as they react together to form products which are written after the arrow.

$CaCO_3 + 2HCl \rightarrow CaCl_2 + CO_2 + H_2O$

Thus $CaCO_3$ and HCl are reactants here whereas $CO_2$ , $CaCl_2$ and $H_2O$ are products.

7 0

3 years ago

Read 2 more answers

When would a cell use Active Transport? Mark all that apply.

Westkost [7]

Answer:

a c e

Explanation:

4 0

3 years ago

Does my body get all its energy from the sun?

kirza4 [7]

Yes, and no. We all should know by know we do need the sun to survive, but we also need for energy is oxygen and the food we eat.

3 0

3 years ago

How many grams of O₂ are required to react completely with 14.6 g of Na to form sodium oxide, Na₂O?

Bad White [126]

The balanced chemical reaction is :

$O_2 + 4Na \ -> \ 2Na_2O$

Number of moles of Na, $n = \dfrac{14.6}{23} = 0.635 \ mol$ .

Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.

So, number of moles of oxygen are :

$n = \dfrac{0.635}{4}\ mole$

So, amount of oxygen required is :

$m = \dfrac{0.635 \times 32}{4}\ gm\\\\m = 5.08 \ gm$

Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.

7 0

3 years ago