Number of particles inside a sugar bowl = 4.4 x 10²³
<h3>Further explanation</h3>
Given
The molar mass of sugar = 342.3 g/mol
mass of sugar = 250 g
Required
Number of particles
Solution
1 mol = 6.02 x 10²³ particles
mol of sugar :
mol = 250 g : 342.3 g/mol = 0.73 mol
Number of particles :
N = n x No
N = 0.73 x 6.02 x 10²³
N = 4.39 x 10²³ ≈ 4.4 x 10²³
answer an element and a compound
Answer:
0.071 is the correct answer using the formula d=m/v
There are 6 Nitrogen atoms
Answer:
74.0 g/mol
Explanation:
Step 1: Write the generic neutralization reaction
HA + NaOH ⇒ NaA + H₂O
Step 2: Calculate the reacting moles of NaOH
At the equivalence point, 33.83 mL of 0.115 M NaOH react.
0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol
Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH
The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.
Step 4: Calculate the molar mass of the acid
3.89 × 10⁻³ moles of HA have a mass of 0.288 g.
M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol
