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3 years ago

Look at the equation CO2 + H2 = CO + H20.

Chemistry

1 answer:

sergejj [24]3 years ago

3 0

Answer:

CO is considered as a product.

Explanation:

A general chemical equation for a combination reaction follows:

To write a chemical equation, we must follow some of the rules:

The reactants must be written on the left side of the direction arrow.

A '+' sign is written between the reactants, when more than one reactants are present.

An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.

The products must be written on the right side of the direction arrow.

A '+' sign is written between the products, when more than one products are present.

For the given chemical equation:

are the reactants in the reaction and are the products in the reaction.

Hence, CO is considered as a product.

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3 years ago

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What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10

vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, $\rm pOH = 14 - pH$

The pH of KOH can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the first case, the concentration of the KOH is $1. 87 \times 10^{-13}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times 10^{-13}\;\rm M ]\\\\&= 12.73\end{aligned}$

Hence, the pH of KOH is 12.73.

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pOH of KOH can be calculated by the formula,

$\rm pOH = \rm -log [OH^{-}]$

The hydroxide concentration of the KOH solution is $5. 81 \times 10^{-3}\;\rm M$

Substituting value in the equation:

$\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm M ]\\\\&= 2.24 \end{aligned}$

Hence, the pOH of KOH is 2.24

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The pH of NaCl can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the third case, the concentration of the NaCl is $1. 00\times 10^{-7}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times 10^{-7}\;\rm M ]\\\\&= 7 \end{aligned}$

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

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3 years ago

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Answer:

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A 8.96-L sample of gas has a pressure of 1.86 atm and a temperature of 94 °C. The sample is allowed to expand to a volume of 11.

Varvara68 [4.7K]

Answer:

Explanation:

Explanation:

All you have to do here is use the ideal gas law equation, which looks like this

−−−−−−−−−−

Here

is the pressure of the gas

is the volume it occupies

is the number of moles of gas present in the sample

is the universal gas constant, equal to

0.0821

atm L

mol K

is the absolute temperature of the gas

Rearrange the equation to solve for

⇒

Before plugging in your values, make sure that the units given to you match those used in the expression of the universal gas constant.

In this case, the volume is given in liters and the pressure in atmospheres, so you're good to go.

Plug in your values to find

3.10

atm

⋅

64.51

9.69

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⋅

0.0821

atm

⋅

mol

⋅

251 K

−−−−−−−−−

The answer is rounded to three

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3 years ago