Explanation:
For multiplication or division, the rule is to count the number of significant figures in each number being multiplied or divided and then limit the significant figures in the answer to the lowest count.
a. 20.0 meters x 0012.65 meters
The numbers are;
20.0 (3 s.f) and 12.65 (4 s.f)
The multiplication gives; 253
Since 253 is already in 3 s.f, that's the answer.
b. 002.5 × 103 meters + 3.50 × 102 meters
The numbers are;
002.5 (2 s.f), 103 (3 s.f), 3.50 (3 s.f) and 102 (3 s.f)
002.5 × 103 = 257.5 = 260 (2 s.f)
3.50 × 102 = 357 = 360 (2 s.f)
260 + 360 = 620
Answer:
Electronic Configuration of calcium ion: Ca²⁺
1s², 2s², 2p⁶, 3s², 3p⁶
Explanation:
Calcium belong to group IIA and known as alkaline earth metals.
- it have two electrons in outer most orbital.
- these outer two electrons are involve in bonding
- calcium lose these two electron and form cation
- cation have 2+ charge
- calcium have total twenty electrons
Electronic Configuration of calcium atom: ²⁰Ca
1s², 2s², 2p⁶, 3s², 3p⁶, 4s²
When calcium ion is form it loses two electron and have 2+ charge on it.
and have total of 18 electrons
So,
Electronic Configuration of calcium ion: Ca²⁺
the last filled orbital will be 3p⁶
1s², 2s², 2p⁶, 3s², 3p⁶
CO(g) +2H2--->CH3OH
2.50g H2*1mol/2g=1.25 mol H2
30.0L CO*1mol/22.4L=1.34 mol CO,
according to reaction 1 mol CO needs 2 mol H2,so 1.34 mol CO need 2.68 mol H2, so 1) limiting teactant is H2 (H)
2)1.25 mol CH3OH will be produced, 1.25 mol*32g/mol=40.0 g CH3OH
3) 1.25 mol H2 needs 0.625 g CO
1.34-0.625=0.715 g CO leftover
I think there might be just 4 or 5 chloropropene.