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3 years ago

USE LETTERS FOR ANSWERS, NO NEED TO EXPLAIN

Chemistry

1 answer:

Deffense [45]3 years ago

6 0

Answer:

Ok:

Explanation:

6a) $Hg + Zn(NO_3)_2\\$

b) NR

c) $Hg_{(l)} + Zn(NO_3)_2 {(aq)}=> NR$

d) Welp, no reaction so i don't know.

7a) $KI + Pb(NO_3)_2$

b) $PbI_2 + KNO_3$

c) All are aqeuous except for PbI2 which is solid

d) $2KI _{(aq)}+ Pb(NO_3)_2_{(aq)} => PbI_2_{(s)} + 2KNO_3_{(aq)}$

Check if that is ok or if my work has any issues :).

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PH of 0,035M HCl? How to count if your calculator hasn't got -lg?

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Given information:

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To determine:

pH of the solution

Explanation:

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Hence the concentration of H+ = Cl- = 0.035M

Now, pH measures the strength of H+ ions in a given solution. It is expressed as:

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3 years ago

Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s

bazaltina [42]

Answer: The time taken by the reaction is 84.5 seconds

Explanation:

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{9}=0.077s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$ ......(1)

where,

k = rate constant = $0.077s^{-1}$

t = time taken for decay process = 50.7 sec

$[A_o]$ = initial amount of the reactant = ?

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Putting values in equation 1, we get:

$0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}$

$[A_o]=3.67M$

Now, calculating the time taken by using equation 1:

$[A]=0.0055M$

$k=0.077s^{-1}$

$[A_o]=3.67M$

Putting values in equation 1, we get:

$0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s$

Hence, the time taken by the reaction is 84.5 seconds

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3 years ago

How equation can show physical states and reaction conditions

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Answer:

Explanation:

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