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Ghella [55]
3 years ago
7

If a person is throwing darts at a target, and shoots three in a row in the same spot on the 20 section outer ring, but none in

the bullseye, this person's throwing could be described as_____.
Chemistry
1 answer:
Gennadij [26K]3 years ago
5 0
Maybe it is frisbee tag
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A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
notsponge [240]

P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

I hope I helped

5 0
3 years ago
Read 2 more answers
# of protons = 48 <br><br> Cadmium <br> Titanium <br> Oxygen <br> Krypton
Dafna11 [192]

Answer:

Cadmium +p= 48

Titanium p=22

Oxygen p=8

Krypton p=36

So the answer is Cadmium which has #48 protons

Explanation:

7 0
2 years ago
If an element has a mass number of 222 and an atomic number of 86, how
svlad2 [7]

Answer:

136

Explanation:

The Mass Number is the combination of the amount of Protons and Neutrons in an element, so if the total mass is 222, and the amount of protons is 86, then you can do 86 + x = 222 to find that x is equal to 136

5 0
3 years ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
Gastric juice in the stomach contains pepsin and sulfuric acid.<br><br><br> TrueFalse
jonny [76]
False, pepsin and hydrochloric acid
5 0
3 years ago
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