3 years ago

How many milliliters of 2.5M HCI are required to exactly neutralize 15 milliliters of 5.0 M NaOH

Chemistry

1 answer:

Novosadov [1.4K]3 years ago

6 0

Answer: 30mL

Explanation:

(2.5)(x)=(5.0m)(15mL)

x=30mL

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a) concentration after 8.8 min:

$8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}$

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b) for concentration to decrease from 0.25M to 0.15M

$t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20$

$t=687s$

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