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Paraphin [41]
3 years ago
6

How many liters of nitrogen gas are needed to make 25 mol of nitrogen trifluoride

Chemistry
1 answer:
ikadub [295]3 years ago
6 0
The reaction between N₂ and F₂ gives Nitrogen trifluoride as the product. The balanced equation is;

N₂ + 3F₂ → 2NF₃

The stoichiometric ratio between N₂ and NF₃ is 1 : 2
Hence, 
  moles of N₂ / moles of F₂ = 1 / 2
  moles of N₂ / 25 mol        =  0.5
           moles of N₂            =  0.5 x 25 mol = 12.5 mol
 
Hence N₂ moles needed  = 12.5 mol

At STP (273 K and 1 atm) 1 mol of gas = 22.4 L

Hence needed N₂ volume = 22.4 L mol⁻¹ x 12.5 mol
                                          = 280 L 
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GrogVix [38]
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3 years ago
Calculate the number of grams of CO that can react with 0.400 kg of Fe2O3.
aleksandr82 [10.1K]

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Explanation:

Given data:

mass of Fe2O3 = 0.400 Kg

mass of CO= ?

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4 years ago
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2-7-1

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