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Novay_Z [31]
4 years ago
6

One car model costs $12,000 and costs an average of $0.10 per mile to maintain. Another car model costs $14,000 and costs $0.08

per mile to maintain. If one of each model is driven the same number of miles, after how many miles would the total cost of one model be the same as the other?
Mathematics
1 answer:
BlackZzzverrR [31]4 years ago
3 0
Answer:
See a solution process below:
Explanation:
Let's call the number of miles driven we are looking for
m
.
The the total cost of ownership for the first car model is:
12000
+
0.1
m
The the total cost of ownership for the second car model is:
14000
+
0.08
m
We can equate these two expressions and solve for
m
to find after how many miles the total cost of ownership is the same:
12000
+
0.1
m
=
14000
+
0.08
m
Next, we can subtract
12000
and
0.08
m
from each side of the equation to isolate the
m
term while keeping the equation balanced:
−
12000
+
12000
+
0.1
m
−
0.08
m
=
−
12000
+
14000
+
0.08
m
−
0.08
m
0
+
(
0.1
−
0.08
)
m
=
2000
+
0
0.02
m
=
2000
Now, we can divide each side of the equation by
0.02
to solve for
m
while keeping the equation balanced:
0.02
m
0.02
=
2000
0.02
0.02
m
0.02
=
100000
After 100,000 miles the total cost of ownership of the two cars would be the same.
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How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

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A series that has common difference.

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A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
A triangle has two sides of lengths 6 and 9
romanna [79]

Answer:

3rd side length can being choice B. 4 ,C. 7,F. 10,  E. 12,

Step-by-step explanation:

brainly.com/question/1451975

6 0
4 years ago
This is the last one I need help with sorry I didn't make this into one post.
marusya05 [52]

Hi There!

Answer:

A.)$15.96

Step-by-step explanation:

3 1/3 * 2.99 = 9.96666666667

1 1/2 * 3.99 = 5.985

9.9666666666 + 5.985 = 15.9516666667 = $15.96

Hope This Helps :)

5 0
3 years ago
−4m + 5 = -15 pls help
Fed [463]

Answer:

m = 5

Step-by-step explanation:

−4m + 5 = -15

-4m = -15 - 5

-4m = -20

m = 5

7 0
3 years ago
Read 2 more answers
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zloy xaker [14]

Combine like terms

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