Answer:
salt i know the answer and even sugar is
Answer:
The molar mass for the solute is 180.8 g/mol
Explanation:
We apply the colligative property of freezing point depression.
The formula is T° freezing pure solvent - T° freezing solution = Kf . m
T° freezing pure solvent - T° freezing solution → ΔT
Kf = 1.86 °C/m
m is molality. We must determine with data given.
Molality are the moles of solute contained in 1 kg of solvent
0° - (-1.8°C) = 1.86 °C/m . m
1.8°C / 1.86 m/°C = m → 0.968 mol/kg
We multiply the molality by kg of solute, to determine the moles
100 g . 1kg/1000 g = 0.1kg → 0.968 mol/kg . 0.1 kg = 0.0968 moles
To find the molar mass we make g/ mol → 17.5 g / 0.0968 mol =
180.8 g/mol
We know that in 1 mole there is Avogadro’s number of atoms(no matter of what kind of mole) 6.02 x 10^23.
In order to find the number of moles we just apply the rule of three.
1 mole.............. 6.02 x 10^23.
x mole..............<span>6.02 x 10^25
x = </span>6.02 x 10^25/6.02 x 10^23. = 10^2 = 100 moles
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