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pogonyaev
4 years ago
8

Explain how the mid-ocean ridge supports the theory of sea floor spreading. help plzzz:(

Chemistry
1 answer:
Sedaia [141]4 years ago
4 0
The ridge of mid ocean b is the answer hope this helps
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Dana is trying to determine if an unknown sample is a pure substance or not. The sample has a cloudy white color, and it seems e
Firdavs [7]

Answer:

Dana filtered the sample and larger granules of the sample were left behind.

Explanation:

If a substance is pure, it will have a uniform composition throughout. It will not separate into particles of various sizes.

One of the characteristics of pure substances is that they are homogeneous. A mixture is definitely made up of particles of various sizes.

Since the particles was filtered and larger granules were left behind, the sample has been separated by a physical method (filtration). Only a mixture can be separated by physical methods. It is not a pure substance.

5 0
3 years ago
How many elements are in the second group? (column)
zavuch27 [327]
Of the periodic table?
6 0
3 years ago
Who taught us how planets move?
alexdok [17]

Answer:

It is <u>KEPLER</u>

Explanation:

Kepler defined the sun's orbit.

okay.

6 0
3 years ago
As the temperature of a liquid solvent increases, the amount of solute that can dissolve in it ________. decreases remains const
Nookie1986 [14]
Answer:
              
<span>As the temperature of a liquid solvent increases, the amount of solute that can dissolve in it <u>increases</u>.

Explanation:
                    The solubility of most solutes in a solvent increases with increase in temperature. This solubility is closely related to the heat of solution, (the heat evolved or absorbed when solute is dissolved in solvent). Hence, majority of solutes when dissolved in solvent absorbs heat and makes the overall heat of solution positive. Hence, in this case more heat provided will increase the rate of solubility.</span>
6 0
3 years ago
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
pogonyaev

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

5 0
3 years ago
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