Hello :
<span>2x + 3 < 19 and 2x − 3 ≤ -7 :
the system :
</span><span>2x + 3 < 19 .....(1)
2x − 3 ≤ -7......(2)
by (1) : 2x </span>< 16
x < 8
by(2) : 2x ≤ -4
x ≤ -2
conclusion : x < 8 and x ≤ -2
The solution set is : x ≤ -2
K=29 is the correct answer
Answer:
3(2x+5)=3 6x+15 = 3 6x = -12 x =-2
9+9x=2x+2 9x-2x= 2-9 7x= -7 x=-1
Step-by-step explanation:
So the rule with multiplying exponents of the same base is
. Apply this rule here:

Next, the rule with converting negative exponents into positive ones is
. Apply this rule here:

<u>Your final answer is 1/49.</u>
<h2>------------------------------------------------</h2>
So an additional rule when it comes to exponents is ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
In this case, your fractional exponent, x^9/7, would be converted to
. However, I had just realized you can further expand this.
Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:
![\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7Bx%5E9%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%2Ax%5E2%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D%20)
Your final answer would be ![x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20x%5Csqrt%5B7%5D%7Bx%5E2%7D%20)
Answer:
I believe it's C
Step-by-step explanation: