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ioda
3 years ago
7

4. In your own words, describe how you can check to see if an ordered pair is a solution to a system of equations,

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer: To figure out if an ordered pair is a solution to an equation, you could perform a test or experiment . Identify the x-value in the ordered pair and plug it into the equation. When you simplify, if the value you get is the same as the value in the ordered pair, then that ordered pair is indeed a solution to the equation.

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The solution set for all real numbers x such that 2x + 3 < 19 and 2x − 3 ≤ -7 is (blank, blank]
fgiga [73]
Hello : 
<span>2x + 3 < 19 and 2x − 3 ≤ -7 :
the system :
</span><span>2x + 3 < 19 .....(1)
2x − 3 ≤ -7......(2)
by (1) : 2x </span>< 16
             x < 8
by(2) : 2x  ≤ -4
           x ≤ -2
conclusion :   x < 8 and  x ≤ -2
The solution set  is : x ≤ -2
3 0
2 years ago
What is the value of k?<br> k = 28<br> k = 29<br> k = 31 <br> k = 42
elena-14-01-66 [18.8K]
K=29 is the correct answer
8 0
3 years ago
Please help me asap!
Pavlova-9 [17]

Answer:

3(2x+5)=3      6x+15  = 3                         6x =  -12       x =-2

9+9x=2x+2             9x-2x= 2-9        7x=  -7          x=-1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Simplify 7^-5/6*7^-7/6
DochEvi [55]

So the rule with multiplying exponents of the same base is x^m*x^n=x^{m+n} . Apply this rule here:

7^{-\frac{5}{6}}*7^{-\frac{7}{6}}=7^{-\frac{5}{6}+{-\frac{7}{6}}}=7^{-\frac{12}{6}}=7^{-2}

Next, the rule with converting negative exponents into positive ones is x^{-m}=\frac{1}{x^m} . Apply this rule here:

7^{-2}=\frac{1}{7^2}=\frac{1}{49}

<u>Your final answer is 1/49.</u>

<h2>------------------------------------------------</h2>

So an additional rule when it comes to exponents is x^{\frac{m}{n}}=\sqrt[n]{x^m}

In this case, your fractional exponent, x^9/7, would be converted to \sqrt[7]{x^9} . However, I had just realized you can further expand this.

Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:

\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}

Your final answer would be x\sqrt[7]{x^2}

3 0
3 years ago
All of the following represent the same function except ____.
Whitepunk [10]

Answer:

I believe it's C

Step-by-step explanation:

4 0
3 years ago
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