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3 years ago

The greatest common factor of 54 and 72 is:

Mathematics

2 answers:

Taya2010 [7]3 years ago

6 0

1,2,3,6,9,18,27,54
1,2,3,4,6,12,18,36,72

Verdich [7]3 years ago

3 0

$54|2\\27|3\\.\ 9|3\\.\ 3|3\\.\ 1|\\54=\fbox2\cdot\fbox3\cdot\fbox3\cdot3\\\\72|2\\36|2\\18|2\\.\ 9|3\\.\ 3|3\\.\ 1|\\72=\fbox2\cdot2\cdot2\cdot\fbox3\cdot\fbox3\\\\GCF(54;\ 72)=\fbox2\cdot\fbox3\cdot\fbox3=\boxed{\boxed{18}}$

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Aloiza [94]

Answer:

1. 16/5 2. 4 3. 15 4. 56 5. 15/2 6. -20 7. -3.333333 8. -23/2 9. no solutions 10. -11/2

Step-by-step explanation:

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3 years ago

34% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mo

tamaranim1 [39]

Answer:

solution below

Step-by-step explanation:

The question says 6 working mother's were selected so n = 6 not 0.6

We are expected to find

P(X = 0,1,2,3,4,4,6)

1. When x = 0

6C0*(0.34)⁰*(0.66)⁶

= 1 *1* 0.827

= 0.0827

2. When X = 1

6C1*(0.34)¹*(0.66)⁵

= 6 x 0.34 x 0.252

= 0.2555

3. When X = 2

6C2*(0.34)²*(0.66)⁴

= 15 x 0.1156 x 0.1897

= 0.3289

4. When x = 3

6C3*(0.34)³*(0.66)³

20 x 0.039304 x 0.2875

= 0.2599

5. When X = 4

6C4*(0.34)⁴*(0.66)²

= 15 x 0.01336 x 0.4356

= 0.8729

6. When x = 5

6C5*(0.34)⁵*(0.66)¹

= 6 x 0.0045 x 0.66

= 0.01782

7. When x = 6

6C6*(0.34)⁶*(0.66)⁰

1 x 0.0015 x 1

= 0.0015

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3 years ago

Amanda wants to buy a new iPod that costs $250. When she gets to the Apple store

malfutka [58]

Answer:

Answer:

15% off 212.5

30% off 175$

Step-by-step explanation:

15+15=30 so

250/100=2.5

2.5x30=75

250-75

8 0

2 years ago

What is (-7/4) (-8/9)

kipiarov [429]

If you are saying (-7/4)*(-8/9) Then it is
1.55555555556
If you are saying something else please message me so I can help better.

5 0

3 years ago

A survey found that the American family generates an average of 17.2 pounds of glass garbage trash each year. Assume the standar

SIZIF [17.4K]

Answer: 0.8137

Step-by-step explanation:

As per given , we have

$\mu= 17.2\ ,\ \sigma=2.5$

Sample size : n= 47

Let $\overline{X}$ be the sample mean o.

Then, the probability that the mean of a sample of 47 families will be between 16.6 and 17.6 pounds will be :

$P(16.6$

$=P(-1.645$

[∵ $z= \dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ ]

$=P(z$

$=0.8636793-(1- 0.9500151)$ [By using p-value calculator]

$=0.8636793-0.0499849=0.8136944\approx0.8137$

Hence, the probability that the mean of a sample of 47 families will be between 16.6 and 17.6 pounds= 0.8137

6 0

3 years ago