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xz_007 [3.2K]
3 years ago
13

How do u solve 2x+15=1

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0
You would subtract 15 on both sides and then you would have 2x=-14 then you divide both sides by 2 and x would equal -7
tangare [24]3 years ago
6 0

Answer:

x = -7

Step-by-step explanation:

2x + 15 = 1

Subtract 15 from both sides of the equation

2x = -14

Divide both sides of the equation by 2

x = -7

Hope this helps :)

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Apply the following transformations to the shape and draw the resulting shape​
Morgarella [4.7K]

Answer:

Step-by-step explanation:

Take the coordinates(0,0)(2, -2)(6, -4)(4, -6) and cut each number in half. Then move each point left 3 and up 2.

4 0
3 years ago
Given Triangle DEF is isosceles and angle D is the vertex angle, Find x, DE, DF, EF
ch4aika [34]

Answer:

x=2;DE,EF=9,DF=5

Step-by-step explanation:

Since DEF is isoceles, you can set the equations

x+7 and 2x+5 equal to each other

x+7=2x+5, now solve for x

-x=-2,

x=2, now plug in for each side

DE,EF=9

DF=3(2)-1=5

4 0
3 years ago
Solve the following equations for x : <br> g = c - x
ZanzabumX [31]

Answer:

\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}

g = c - x \\ c - x = g \\  - x = g - c \\ x =  - g - c

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5 0
2 years ago
X+2(x+y)=7<br> 3(x-y)=1-2y<br><br> What is x&amp;y????<br><br><br><br> Please answer asap!!!!
Shkiper50 [21]
X= -x over 2 (negative x as a fraction and 2 is the denominator) minus y+ (seven as the numerator over 2 as the denominator).
Solve for y by simplify both sides with inverse operations, then isolate the variable and you get,  y = 3x - 1.
4 0
3 years ago
The town of madison has a population of 25,000. The population is increasing by a factor of 1.12 each year. Write a function tha
GaryK [48]
<h3>The population P(t) at the end of year t is   P(t)   = 25,000 \times (1.12)^t</h3>

Step-by-step explanation:

The initial population of town of Madison = 25,000

The rate at which the population is increasing = 1.12 times

So, the increase in population first year  :

( the initial population)  x (1.12)^1  = 1.12 x ( 25,000)  

= 28,000

So, the population at the end of first year = 28,000

Similarly, the increase in population second year  :

( the initial population)  x (1.12)²  =  ( 25,000)   x (1.12)²

= 31,360

So, the population at the end of second year =31,360

Now, to calculate the population in t years from now:

The population P(t) at the end of year t is

P(t)   = 25,000 \times (1.12)^t

5 0
3 years ago
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