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3 years ago

A solid cylindrical steel rod has a base area of 100 cm2 and a length of 50 cm. What is the volume of the steel rod?

Mathematics

2 answers:

natulia [17]3 years ago

4 0

Answer:

5000 cm3

Step-by-step explanation:

find radius

cal the volume

Nastasia [14]3 years ago

3 0

Answer:

The volume of the steel rod is $5,000\ cm^{3}$

Step-by-step explanation:

we know that

The volume of the cylinder is equal to

$V=Bh$

where

B is the area of the base of cylinder

h is the height or length of the cylinder

In this problem we have

$B=100\ cm^{2}$

$h=50\ cm$

substitute

$V=100*50=5,000\ cm^{3}$

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2 years ago

A group of 100 students took a quiz. Their average score was 76 points. If the average score for the boys was 80 points and the

sveta [45]

Answer:

The number of girls participated in quiz is 40 .

Step-by-step explanation:

Given as :

Total number of students took quiz = 100

Average score of 100 students = 76 points

The Average score of boys = 80 points

The Average score of girls = 70 points

Let The number of boys participated in quiz = b

Let The number of girls participate in quiz = g

Now, According to question'

Total number of students took quiz = number of boys participated in quiz + number of girls participated in quiz

Or, b + g = 100 ........A

<u>Again</u>

∵ Average score of 100 students = 76 points

∴ Total score of 100 students = 76 × 100 = 7600

So, Average score of boys × number of boys participated + Average score of girls × number of girls participated = Total score of 100 students

Or, b × 80 + g × 70 = 7600

Or, 80 b + 70 g = 7600 .........B

Now, Solving equation A and B

(80 b + 70 g ) - 70 ×( b + g ) = 7600 - 70 × 100

I.e (80 b - 70 b) + (70 g - 70 g) = 7600 - 7000

Or, 10 b + 0 = 600

∴ b = $\dfrac{600}{10}$

i.e b = 60

So, The number of boys participated in quiz = b = 60

Put the value of b into eq A

∵ b + g = 100

So, g = 100 - b

Or, g = 100 - 60

i.e g = 40

So, The number of girls participated in quiz = g = 40

Hence, The number of girls participated in quiz is 40 . Answer

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2 years ago

In a chess club the probability that Shaun will beat Mike is 3/8 .

romanna [79]

Answer:

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So $1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8}$ probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So $1 - \frac{5}{7} = \frac{2}{7}$ probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

$p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786$

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

3 0

2 years ago

What is the 250th term of this sequence. Please explain. 4, 9,14,19,24

Rudik [331]

A1 = first term = 4
a2 = second term = a1+5 = 4+5 = 0
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an=4+5(n-1).

Is this correct? Let's check it and find out.
What is your prediction for a2? Here, n = 2. Then a2 = 4+5(2-1), or 4+5, or 9. That agrees with the given sequence rule.

Thus, the 250th term would be 4+5(250-1). Evaluate this, please.

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