Answer:
Before:


After:




Explanation:
<u>Conservation of Momentum</u>
Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

After the collision, they have speeds of v1f and v2f and the total momentum is

Impulse J is defined as

Where F is the average impact force and t is the time it lasted
Also, the impulse is equal to the change of momentum

As the total momentum is conserved:


We can compute the speed of the second object by solving the above equation for v2f

The given data is


a) The impulse will be computed at the very end of the answer
b) Before the collision


c) After collision

Compute the car's speed:


And the car's momentum is

The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.
We can compute the impulse for each object

The force can be computed as

The force on the car has the same magnitude and opposite sign
The final speed of the toy car at the end of the given time period is 3.58 m/s.
The given parameters;
- distance traveled by the car, s = 1.2 m
- time of motion of the car, t = 0.67 s
- initial velocity of the car, u = 0
The acceleration of the car is calculated as;

The final velocity of the toy car is calculated as;

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.
Learn more here: brainly.com/question/20352766
B, do earthworms prefer bright light or darkness!
(-5)/3 - 6/(-5)
You can solve it now :)
Answer:
A) B = 0.009185 T
B) Drection is negative y-direction
Explanation:
A) We are given;
Speed(v) = 2.5 x 10^(7) m/s
Acceleration (a) = 2.2 x 10^(13) m/s²
We also know that charge of proton(q) = 1.6 x 10^(-19)
Mass of proton(m) = 1.67 x 10^(-27)
Now, Since the proton is moving by circular motion, this force is equal to the centripetal force which is given as;
F = qvBsinθ = ma
Since perpendicular, θ = 90°
And so, sinθ = sin 90 = 1
Thus, qvB = ma
Making B the subject gives;
B = ma/qv
B = (1.67 X 10^(-27) X 2.2 X 10^13)) / (1.6 X 10^(-19) X 2.5 X 10^(7))
= 0.009185 T
B) By use of Flemings right hand rule, we can see that the middle finger points toward negative y-direction, so the magnetic field is in the negative y-direction