Answer:
prerecorded magnetic tapes used for noncommercialplayback of sound on audio equipment.
Explanation:
study hard:)
¡Hola!
For this problem, first, lets recabe information:
v = 0 m/s
t = 3 s
g = 9,82 m/s²
v' = ?
d = ?
First, for calculate the final velocity:
v' = v + g * t
v' = 0 m/s + 9,82 m/s² * 3 s
v' = 29,46 m/s
Now, for calculate how far did it fall:
d = v * t + g * t^2 / 2
Like v = 0 m/s, we can simplificate equation:
d = g * t^2 / 2
d = 9,82 m/s² * (3 s)^2 / 2
d = 9,82 m/s² * 9 s² / 2
d = 88,38 m / 2
d = 44.19 m
¡Buena suerte!
<span> The quantity that is determined by the distance moved and the force used is called work.
To determine the amount of work being done you would simply multiply the distance moved and the amount of force used.
HOPE THIS HELPS! ^_^</span>
Convert 220 lb to kg.
220/2.2 = 100kg.
W = Fd (In this case, F is the weight)
W = (100)(2)
W = 200J
P = W/t
P = (200)/(1.2)
P = 166.67W
The horizontal force applied is 160 N while the velocity is 2.03 m/s.
<h3>What is the speed of the car?</h3>
The work done by the car is obtained as the product of the force and the distance;
W = F x
F = ?
x = 30.0 m
W = 4,800 J
F = 4,800 J/30.0 m
F = 160 N
But F = ma
a = F/m
a = 160 N/2.30 ✕ 10^3-kg
a= 0.069 m/s
Now;
v^2 = u^2 + 2as
u = 0/ms because the car started from rest
v = √2as
v = √2 * 0.069 * 30
v = 2.03 m/s
Learn more about force and work:brainly.com/question/758238
#SPJ1