All of them apply because they all are doing some thing to move
It stays costant cause of the soultion
Answer:
The satellite has a period of 204.90 days
Explanation:
The period can be determine by means of Kepler's third law:
(1)
Where T is the period of revolution and r is the radius.
![\sqrt{T^{2}} = \sqrt{r^{3}}](https://tex.z-dn.net/?f=%5Csqrt%7BT%5E%7B2%7D%7D%20%3D%20%5Csqrt%7Br%5E%7B3%7D%7D)
(2)
The distance between the moon and the Earth has a value of 384400 km, therefore:
![r = (384400km)*(0.50)](https://tex.z-dn.net/?f=r%20%3D%20%28384400km%29%2A%280.50%29)
![r = 192200 km](https://tex.z-dn.net/?f=r%20%3D%20192200%20km)
Finally, equation 2 can be used:
![T = \sqrt{(192200)^{3}}](https://tex.z-dn.net/?f=T%20%3D%20%5Csqrt%7B%28192200%29%5E%7B3%7D%7D)
![T = 84261672 km](https://tex.z-dn.net/?f=T%20%3D%2084261672%20km)
However, the period can be expressed in days, to do that it is necessary to make the conversion from kilometers to astronomical units:
An astronomical unit (AU) is the distance between the Earth and the Sun (
)
⇒ ![0.561 AU](https://tex.z-dn.net/?f=0.561%20AU)
But 1 year is equivalent to 1 AU according to Kepler's third law, since 1 year is the orbital period of the Earth.
⇒ ![0.561 year](https://tex.z-dn.net/?f=0.561%20year)
⇒ ![204.90 days](https://tex.z-dn.net/?f=204.90%20days)
![T = 204.90 days](https://tex.z-dn.net/?f=T%20%3D%20204.90%20days)
Hence, the satellite has a period of 204.90 days.
Red Giants are the stars that currently in the late phase of the Stellar Revolution. One of the main features of a red giant is its variations on brightness.
Red Giants are formed because of the constant helium-burning process from the stars (which keep making it bigger and bigger) to the point where it almost ran out of it.